anonymous
  • anonymous
What is the concentration of nitrate ion in a 425 mL solution containing 32.0 g of Mg(NO3)2 (M= 148.3)?
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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aaronq
  • aaronq
The correct way to do these types of questions it to write and equation for the dissociation of the ionic compound and then find the moles of the ion. Then use the formula for molarity: \(\sf Molarity=\dfrac{moles}{liters~of~solution}\)
anonymous
  • anonymous
How do I write an equation for the disassociation of the compound?
aaronq
  • aaronq
You have to do it based on the charges of the ions (nitrate ion is a polyatomic ion, one of several you should memorize). \(\sf Mg(NO_3)_2\rightarrow Mg^{2+}+2~NO^-_3\)

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anonymous
  • anonymous
So now I find the moles?
aaronq
  • aaronq
use the mass of the compound and the coefficients, just like you would if you had to find the theoretical yield of a product.
anonymous
  • anonymous
The mass of 2NO3 is 124.02
aaronq
  • aaronq
I'll simplify it for ya, find the moles of Mg(NO3)2, multiply them by two. these are the moles of the nitrate ion, now divide this number by the volume of the solution (you have to convert it to liters first)
anonymous
  • anonymous
Okay so Mg(NO3)2 is 148.33 g/mol *2= 296.66 296.66/.425 = 698.02
anonymous
  • anonymous
Wait did I use the wrong amount? I should have used 32.0 g instead of 425 mL...right?
aaronq
  • aaronq
you have to first find the moles of Mg(NO3)2, \(\sf moles=\dfrac{mass}{Molar~mass}\)
anonymous
  • anonymous
32g/ 148.33= .2157
aaronq
  • aaronq
now do the rest of what i said earlier. ...multiply by two. these are the moles of the nitrate ion, now divide this number by the volume of the solution (you have to convert it to liters first)
anonymous
  • anonymous
.2157*2= .4314 .4314/.425= 1.0151 M?
aaronq
  • aaronq
yup! thats it
anonymous
  • anonymous
Thank you for being patient!! I appreciate your help!
aaronq
  • aaronq
no problem! i'm glad you put in some effort, a lot of people just give up.

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