thecrazy_t
  • thecrazy_t
(QUICK) The vertex of this parabola is at (2, -1). When the y-value is 0, the x-value is 5. What is the coefficient of the squared term in the parabola's equation? (QUICK) The vertex of this parabola is at (2, -1). When the y-value is 0, the x-value is 5. What is the coefficient of the squared term in the parabola's equation? https://gyazo.com/359a21c5c3450dd4b7aec64017e5246e
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
campbell_st
  • campbell_st
you have h 2 and k = -1 substitute them into \[y = a(x -h)^2 + k\] next use the point (5, 0) substitute x = 5 and y = 0 and solve for a
thecrazy_t
  • thecrazy_t
so far 0=a(5-2)^2+-1 correct? then solve that as normal for a
thecrazy_t
  • thecrazy_t
is not one of my options though

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

campbell_st
  • campbell_st
you need to calculate the answer so 0 = 9a - 1 now solve for a, that will be the coefficient of x^2

Looking for something else?

Not the answer you are looking for? Search for more explanations.