anonymous
  • anonymous
Please i need some help
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
1 Attachment
Astrophysics
  • Astrophysics
Try to limit 1 question per post
Astrophysics
  • Astrophysics
\[y=\frac{ 4x^2+12x }{ x^2+x-6 }\] so lets do this one

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anonymous
  • anonymous
#6? ok
Astrophysics
  • Astrophysics
Vertical asymptotes are where the function is undefined so solve for the denominator \[x^2-x-6\]
Astrophysics
  • Astrophysics
Simply factor the expression and it will give you your VA
anonymous
  • anonymous
okay i got -2 and 3
Astrophysics
  • Astrophysics
It's x^2+x-6 not x^2-x-6 oops
Astrophysics
  • Astrophysics
So it's the other way around, x = 2 and x = -3
anonymous
  • anonymous
its either C or B but how do you tell a difference
Astrophysics
  • Astrophysics
What are you solving for when you factor, it's in the post befor elol
anonymous
  • anonymous
I want to say that C is the correct one
anonymous
  • anonymous
If your expression is x equal to a number, it is a vertical line since the x value is fixed while the y value can be anything. If it's y equals a number, it is a horizontal line. B is giving two vertical lines while C is giving two horizontal lines. Also, to find the asymptotes you set the denominator equal to zero and solve, so your equations would come out like this: x^2+x-6=0 (x-2)(x+3)=0 x=2 and x=3 are the equations of your asymptotes.
anonymous
  • anonymous
So it was B thank you

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