anonymous
  • anonymous
Solve the equation of 2log (2y + 4) = log 9 + 2log (y -1). A. 3 B. 5 C. 7 D. 21
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
@Hero @ParthKohli @iambatman
anonymous
  • anonymous
first write both sides of the equation as a single log then ignore the logs
anonymous
  • anonymous
that is one way, there may be an easier way

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anonymous
  • anonymous
Ok so then its B correct?
anonymous
  • anonymous
@TheSmartOne @AlexandervonHumboldt2
anonymous
  • anonymous
\[2\log(2y+4)=\log9+2\log(y-1)\]
anonymous
  • anonymous
\[2\log(2y+4)-2\log(y-1)=\log9\]
anonymous
  • anonymous
\[\log(2y+4)^2-\log(y-1)^2=\log9\]
anonymous
  • anonymous
\[\log \frac{ (2y+4)^2 }{ (y-1)^2 }=\log9\]
anonymous
  • anonymous
\[\log(\frac{ 2y+4 }{ y-1 })^2=\log9\]
anonymous
  • anonymous
Then,cancel both log
anonymous
  • anonymous
\[(\frac{ 2y+4 }{ y-1 })^2=9\]
anonymous
  • anonymous
\[\frac{ 2y+4 }{ y-1 }=\sqrt{9}\]
anonymous
  • anonymous
\[\frac{ 2y+4 }{ y-1 }=3\]
anonymous
  • anonymous
Multiply both sides by y-1
anonymous
  • anonymous
\[\frac{ 2y+4 }{ y-1 }\times~(y-1)=3\times(y-1)\]
anonymous
  • anonymous
\[2y+4=3(y-1)\]
anonymous
  • anonymous
Expand the right side
anonymous
  • anonymous
\[2y+4=3y-3\]
anonymous
  • anonymous
Then,combine like terms and solve for y...
anonymous
  • anonymous
@brooke_ivy99

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