iwanttogotostanford
  • iwanttogotostanford
ll
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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iwanttogotostanford
  • iwanttogotostanford
@Cardinal_Carlo
iwanttogotostanford
  • iwanttogotostanford
@Cardinal_Carlo
iwanttogotostanford
  • iwanttogotostanford
@Cardinal_Carlo

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anonymous
  • anonymous
Okay, now I see it.
iwanttogotostanford
  • iwanttogotostanford
ok, thanks!
anonymous
  • anonymous
This one's a mouthful.
iwanttogotostanford
  • iwanttogotostanford
i know :-(
anonymous
  • anonymous
So our function is this: \[f(x) = \frac{ (x - 6)(x + 3)(x + 4) }{ (x + 6)(x - 3)(x - 4) }\] Undefined functions are, in this case, when the denominator equals to zero. So we only need the bottom half of this fraction: \[0 = (x + 6)(x - 3)(x - 4)\] This would give us our undefined x-values. \[x = -6\]\[x = 3\]\[x = 4\] These are undefined x-values because when plugged in, they make the denominator equal to zero, and therefore makes the entire function f(x) undefined.
iwanttogotostanford
  • iwanttogotostanford
oh wow, ok thank you
iwanttogotostanford
  • iwanttogotostanford
how are you so good at every math? @Cardinal_Carlo I need to be this good at math haha!
iwanttogotostanford
  • iwanttogotostanford
I have just two more left! I could really use help !
anonymous
  • anonymous
Just post them up and close this one ^_^

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