cmtboy2
  • cmtboy2
ill fan
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
k
anonymous
  • anonymous
and medal
cmtboy2
  • cmtboy2
ya

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cmtboy2
  • cmtboy2
1 Attachment
DangerousJesse
  • DangerousJesse
Hint: like terms are terms who share the same variables.
cmtboy2
  • cmtboy2
so.. it's A,B,D
cmtboy2
  • cmtboy2
right
DangerousJesse
  • DangerousJesse
It's A,B,C,D
ktbug3
  • ktbug3
no only one letter off try again:) d is incorrect because it has n and nsquared so it is not the same but a and b are correct
ktbug3
  • ktbug3
D IS INCORRECT i just did this in school and D is incorrect
ktbug3
  • ktbug3
d is incorrect because when you have a regular variable and variable squared and cubed together they are not alike so n squared n and n cubed are not like terms. make sense?
cmtboy2
  • cmtboy2
ok I got 4 more
DangerousJesse
  • DangerousJesse
Oh jeez I didn't even notice that. Great job :)
cmtboy2
  • cmtboy2
1 Attachment
ktbug3
  • ktbug3
thanks :)
cmtboy2
  • cmtboy2
1 Attachment
ktbug3
  • ktbug3
what do you think it is
cmtboy2
  • cmtboy2
b
ktbug3
  • ktbug3
i will tell you if you are correct
ktbug3
  • ktbug3
no because the first one has a n and the 2nd has an m
ktbug3
  • ktbug3
try again
cmtboy2
  • cmtboy2
um.. a
anonymous
  • anonymous
correct
ktbug3
  • ktbug3
no there is an m and an n it is not a try c:)
cmtboy2
  • cmtboy2
c
ktbug3
  • ktbug3
yah;)
cmtboy2
  • cmtboy2
1 Attachment
ktbug3
  • ktbug3
g2g sorry bye:0) hope i helped
anonymous
  • anonymous
This was the question, right: \[2m^2-4n^2+3m-6m^2-2m+7n^2\] That simplifies \[=2m^2-6m^2+3m-2m+7n^2-4n^2\]\[=-4m^2+m+3n^2\] Which is the answer a not c.
cmtboy2
  • cmtboy2
im going with c dude im sorry
anonymous
  • anonymous
Just look at the calculations, it is not c.
anonymous
  • anonymous
Please show me how you got the answer "c".
cmtboy2
  • cmtboy2
ok let's do this one
1 Attachment
anonymous
  • anonymous
What do you think?
cmtboy2
  • cmtboy2
I have no clue what this one is
anonymous
  • anonymous
You have the growth of each child. And you want the growth of them both together. So you need to add the individuals growths. \[5x-1+2x+3=?\]
cmtboy2
  • cmtboy2
9x
cmtboy2
  • cmtboy2
5x−1+2x+3=9x
anonymous
  • anonymous
\[5x+2x=7x\]\[-1+3=2\] So \[5x+2x-1+3=?\]
cmtboy2
  • cmtboy2
5x+2x-1+3=9x
anonymous
  • anonymous
No, it is \[5x+2x-1+3=7x+2\] You cannot add the +2 into the x's, they are not the same
anonymous
  • anonymous
Just like you cant say 7 apples + 2 bananas = 9 apples
cmtboy2
  • cmtboy2
oh sorry
anonymous
  • anonymous
No worries
cmtboy2
  • cmtboy2
I got two more
cmtboy2
  • cmtboy2
1 Attachment
anonymous
  • anonymous
First calculate the sum of Thomas's expression, just like we did with the last question. And then calculate Kellys expression. Now you subtract them from each other and find the difference.
anonymous
  • anonymous
So we start with Thomas's expressions: \[3x+7+2x-3=?\]
cmtboy2
  • cmtboy2
3x+7
anonymous
  • anonymous
Yes that is the first expression he took from the bag. The second is 2x - 3. So add those together
cmtboy2
  • cmtboy2
add 3x+7 to 2x - 3
anonymous
  • anonymous
Yes, what is that?
anonymous
  • anonymous
\[3x+7+2x-3=?\]
cmtboy2
  • cmtboy2
9x
cmtboy2
  • cmtboy2
right
anonymous
  • anonymous
No
cmtboy2
  • cmtboy2
?
anonymous
  • anonymous
You need to keep the x's and the other numbers seperate
anonymous
  • anonymous
You can imagine the x's as apples and the other numbers as bananas.
cmtboy2
  • cmtboy2
:/
anonymous
  • anonymous
\[3x+2x+7-3=5x+4\]
cmtboy2
  • cmtboy2
2+3=5 and 7-3=4
cmtboy2
  • cmtboy2
1 Attachment
cmtboy2
  • cmtboy2
last one
anonymous
  • anonymous
Yes
anonymous
  • anonymous
Yes, now remember it is 5x
ktbug3
  • ktbug3
how did you do on the grade

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