ill fan

- cmtboy2

ill fan

- Stacey Warren - Expert brainly.com

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- jamiebookeater

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- anonymous

k

- anonymous

and medal

- cmtboy2

ya

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## More answers

- cmtboy2

##### 1 Attachment

- DangerousJesse

Hint: like terms are terms who share the same variables.

- cmtboy2

so.. it's A,B,D

- cmtboy2

right

- DangerousJesse

It's A,B,C,D

- ktbug3

no only one letter off try again:) d is incorrect because it has n and nsquared so it is not the same but a and b are correct

- ktbug3

D IS INCORRECT i just did this in school and D is incorrect

- ktbug3

d is incorrect because when you have a regular variable and variable squared and cubed together they are not alike so n squared n and n cubed are not like terms. make sense?

- cmtboy2

ok I got 4 more

- DangerousJesse

Oh jeez I didn't even notice that. Great job :)

- cmtboy2

##### 1 Attachment

- ktbug3

thanks :)

- cmtboy2

##### 1 Attachment

- ktbug3

what do you think it is

- cmtboy2

b

- ktbug3

i will tell you if you are correct

- ktbug3

no because the first one has a n and the 2nd has an m

- ktbug3

try again

- cmtboy2

um.. a

- anonymous

correct

- ktbug3

no there is an m and an n it is not a try c:)

- cmtboy2

c

- ktbug3

yah;)

- cmtboy2

##### 1 Attachment

- ktbug3

g2g sorry bye:0) hope i helped

- anonymous

This was the question, right: \[2m^2-4n^2+3m-6m^2-2m+7n^2\] That simplifies \[=2m^2-6m^2+3m-2m+7n^2-4n^2\]\[=-4m^2+m+3n^2\] Which is the answer a not c.

- cmtboy2

im going with c dude im sorry

- anonymous

Just look at the calculations, it is not c.

- anonymous

Please show me how you got the answer "c".

- cmtboy2

ok let's do this one

##### 1 Attachment

- anonymous

What do you think?

- cmtboy2

I have no clue what this one is

- anonymous

You have the growth of each child. And you want the growth of them both together. So you need to add the individuals growths. \[5x-1+2x+3=?\]

- cmtboy2

9x

- cmtboy2

5x−1+2x+3=9x

- anonymous

\[5x+2x=7x\]\[-1+3=2\] So \[5x+2x-1+3=?\]

- cmtboy2

5x+2x-1+3=9x

- anonymous

No, it is \[5x+2x-1+3=7x+2\] You cannot add the +2 into the x's, they are not the same

- anonymous

Just like you cant say 7 apples + 2 bananas = 9 apples

- cmtboy2

oh sorry

- anonymous

No worries

- cmtboy2

I got two more

- cmtboy2

##### 1 Attachment

- anonymous

First calculate the sum of Thomas's expression, just like we did with the last question. And then calculate Kellys expression. Now you subtract them from each other and find the difference.

- anonymous

So we start with Thomas's expressions: \[3x+7+2x-3=?\]

- cmtboy2

3x+7

- anonymous

Yes that is the first expression he took from the bag. The second is 2x - 3. So add those together

- cmtboy2

add 3x+7 to 2x - 3

- anonymous

Yes, what is that?

- anonymous

\[3x+7+2x-3=?\]

- cmtboy2

9x

- cmtboy2

right

- anonymous

No

- cmtboy2

?

- anonymous

You need to keep the x's and the other numbers seperate

- anonymous

You can imagine the x's as apples and the other numbers as bananas.

- cmtboy2

:/

- anonymous

\[3x+2x+7-3=5x+4\]

- cmtboy2

2+3=5 and 7-3=4

- cmtboy2

##### 1 Attachment

- cmtboy2

last one

- anonymous

Yes

- anonymous

Yes, now remember it is 5x

- ktbug3

how did you do on the grade

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