anonymous
  • anonymous
Choose the missing step in the given solution to the inequality −6x − 10 > 14 + 2x. −6x − 10 > 14 + 2x _______________ −8x > 24 x < −3 −4x − 10 > 14 −8x − 10 > 14 −4x − 10 < 14 −8x − 10 < 14
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
XhawaiiangirlX
  • XhawaiiangirlX
I believe it is step 1. Because : |2x - 4| - 3 = 3 |2x - 4| = 3 + 3 (not 3 - 3)
anonymous
  • anonymous
thank you sooo much can you please help me with some others?
anonymous
  • anonymous
@XhawaiiangirlX

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More answers

texaschic101
  • texaschic101
missing step : -8x - 10 > 14
anonymous
  • anonymous
Solve for L: A = L ⋅ W ⋅ H L = A times W over H L = W times H over A L = A over quantity W times H L = W over quantity H times A
texaschic101
  • texaschic101
divide both sides by WH and what do you get ?
anonymous
  • anonymous
a*w*h=l
texaschic101
  • texaschic101
A = LWH -- divide by WH A/WH = L
texaschic101
  • texaschic101
third one is your answer. Understand ?
anonymous
  • anonymous
yes thank you sooo much!!!! can you please help me with a few more
texaschic101
  • texaschic101
I can try
texaschic101
  • texaschic101
ask away
anonymous
  • anonymous
The table below shows two equations: Equation 1 |3x − 1| + 7 = 2 Equation 2 |2x + 1| + 4 = 3 Which statement is true about the solution to the two equations? Equation 1 and equation 2 have no solutions. Equation 1 has no solution and equation 2 has solutions x = 0, 1. The solutions to equation 1 are x = −1.3, 2 and equation 2 has no solution. The solutions to equation 1 are x = −1.3, 2 and equation 2 has solutions x = 0, 1.
anonymous
  • anonymous
?
texaschic101
  • texaschic101
| 3x - 1 | + 7 = 2 --- subtract 7 from both sides | 3x - 1 | = 2 - 7 | 3x - 1 | = -5 3x - 1 = -5 -(3x - 1) = -5 3x = -5 + 1 -3x + 1 = -5 3x = -4 -3x = -5 - 1 x = -4/3 -3x = -6 x = 2 so x = -4/3(or -1.3) and 2 | 2x + 1| + 4 = 3 | 2x + 1| = 3 - 4 | 2x + 1 | = -1 2x + 1 = -1 -(2x + 1) = -1 2x = -1-1 -2x - 1 = -1 2x = -2 -2x = -1 + 1 x = -1 -2x = 0 x = 0 so we have x = -1 and 0 In that last answer choice...is it supposed to be (in eq 2)..x = 0 and -1 ?
texaschic101
  • texaschic101
I am not getting any of your answer choices...closest I am coming to is the last one...but I am getting -1 instead of 1
anonymous
  • anonymous
Choose the correct description of the graph of the compound inequality x − 3 < −11 or x + 5 greater than or equal to 14. A number line with a closed circle on −8, shading to the left, and an open circle on 9, shading to the right A number line with an open circle on −8, a closed circle on 9, and shading in between A number line with an open circle on −8, shading to the left, and a closed circle on 9, shading to the right A number line with a closed circle on −8, an open circle on 9, and shading in between
texaschic101
  • texaschic101
x - 3 < -11 x < -11 + 3 x < - 8 x + 5 >= 14 x >= 14 - 5 x >= 9 so we have a number line with an open circle on -8 shading to the left and a closed circle on 9, shaded to the right
anonymous
  • anonymous
In a certain county, the number of charter schools is 6 less than twice the number of alternative schools. We know that there are 52 charter schools in the county. How many alternative schools are in the county? 58 44 29 23
texaschic101
  • texaschic101
c = 2a - 6 c = 52 so we sub 52 = 2a - 6 52 + 6 = 2a 58 = 2a 58/2 = a 29 = a....29 alternative schools
anonymous
  • anonymous
the last one Solve for x. −ax + 3b > 5 x > the quantity 3 times b minus 5 all over a x > the quantity 5 minus 3 times b all over negative a x < the quantity 3 times b plus 5 all over a x < the quantity negative 3 times b plus 5 all over negative a
texaschic101
  • texaschic101
-ax + 3b > 5...solving for x -ax > -3b + 5 x < (-3b+5)/-a....last answer choice
anonymous
  • anonymous
thank you soooo much, you have no clue how much you helped me, you are amazing!!!!
texaschic101
  • texaschic101
lol...I try...happy to help :)
anonymous
  • anonymous
Solve for H: A = L ⋅ W ⋅ H H = A times W over L H = W times L over A H = L times A over W H = A over quantity L times W
anonymous
  • anonymous
@texaschic101

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