I need sombidy to show meh the steps how to solve multistep inequality

- AloneS

I need sombidy to show meh the steps how to solve multistep inequality

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- schrodinger

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- AloneS

Solve the inequality 12x < 22 + x.
I have no idea

- anonymous

awnsers

- anonymous

?

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## More answers

- AloneS

whaa??

- anonymous

what are your awnsers

- AloneS

x < 1/2
x > 1/2
x < 2
x > 2

- anonymous

c

- anonymous

c

- anonymous

i promise

- AloneS

geez guys i'm asking the steps

- anonymous

well you got the awnser ;)

- Nnesha

lets change the inequality sign to an equal for a sec
12x=22+x
do you know how to solve for x ?

- AloneS

umm yeah so far i got x=2

- Nnesha

how did you get that what was your first step ?

- AloneS

well i isolated 11x =22

- Nnesha

how did you get 11x ?? :=))

- AloneS

i ..so i subtracted 12 from 22..
geez i made it more confusing

- Nnesha

12-22= isn't 11

- AloneS

yeah it's 10

- Nnesha

\[\rm 12x< 2+x\] to solve for x you need to get all x's term on one side of the inequality sign

- Nnesha

so to move x to the left side what would you do ?

- AloneS

umm..my bad ..i think i should take 12 cuz it's with x and 12x-x?

- Nnesha

yep in order to get x to the left side you should subtract x both sides
and remember x is same as 1x
so 12x-x <22
now simplify combine like terms

- AloneS

oh i actually don't know

- Nnesha

combine like terms
12x-x= ????

- AloneS

12x-x(1) will be 11
O_o i understand ,now i see where you get 11

- AloneS

wait so what is my next step @Nnesha

- Nnesha

right so 11x<22
now to isolate x how would you get rid of 11 ?

- AloneS

so i think umm..wait how do i get rid of x??

- Nnesha

you need to keep the x at left side
to solve for x you should move 11 to the right side
remember we need x itself at left side

- Nnesha

it's 11 times x
in order to cancel out the 11 what would you do ?
would add 11 subtract divide or multiply ?

- AloneS

i guess i 'l take 2

- Nnesha

what do you mean ?

- AloneS

11x<22?

- Nnesha

yes after subtracting x both sides
we get 11x < 22

- AloneS

so i guess it should be 2??

- Nnesha

how did you get 2?
how did you cancel out the 11 ?

- AloneS

cuz 2*11 isn't it's 22

- Nnesha

remember
it's `11 times x` to cancel out 11 you should do opposite of multiplication

- Nnesha

that's correct (when u know the answer choices )

- AloneS

ummm i a :/ctually didn't look thrue answer choices

- AloneS

yeah i guess it's C

- AloneS

thx @Nnesha very much>3!!now i can solve another one on my own!!

- Nnesha

yes
but 11x<22 you should divide both sides to cancel out 11 and remember when we divide or multiply by negative sign we must flip the inequality sign
for example \[-2x \color{Red}{<}6 \] to solve for xx you should divide both sides by `-2`
\[x \color{reD}{>} -3\]
bec i divided both sides by negative number is i flipped the fraction `<` to `>`

- Nnesha

np!

- AloneS

@Nnesha >3

- anonymous

told ya c

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