Jellybot23
  • Jellybot23
How would you turn this equation for an ellipse 2(x+4)^2 + 3(y-1)^2 = 24 into standard form??
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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tkhunny
  • tkhunny
Which Standard form is that? Perhaps multiply out the squares, collect like terms, and you will be close?
Jellybot23
  • Jellybot23
Well isn't standard form (x-h)^2 / a^2 + (y-k)^2 / b^2 = 1?
Jellybot23
  • Jellybot23
@tkhunny

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tkhunny
  • tkhunny
Yes, that is a standard form for an ellipse. That's why I asked. Just divide by 24 to get that standard form, There is also the standard quadratic form: \(ax^{2} + bxy + cy^{2} + dx + ey + f = 0\) In our case, b = 0, but everything else might be there.
Jellybot23
  • Jellybot23
Would I have to simplify because there is a 2 in front of (x+4) and a 3 in front of (y-1)? @tkhunny
tkhunny
  • tkhunny
Just divide by 24. \(\dfrac{2x^{2}}{24} = \dfrac{x^{2}}{12}\)
Jellybot23
  • Jellybot23
Okay that's what I thought, but I wanted to make sure! I haven't dealt with ellipse equations yet this year where the bottom number wasn't a Perfect square, so I was a little disoriented haha Thank you!
tkhunny
  • tkhunny
Next time, SHOW what you thought. It makes for more pleasant conversation. :-)

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