CloverRacer
  • CloverRacer
Need help with algebra 2 question! See attachment.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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CloverRacer
  • CloverRacer
1 Attachment
mathmale
  • mathmale
Please look at the given formula. Copy it down. Note that [H+] is given and is 4.3*10^(-14).
mathmale
  • mathmale
Just substitute this VALUE for [H+] into the formula, calculate the log, and then put a negative sign in front of it.

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CloverRacer
  • CloverRacer
so pH = -log4.3*10^(-14)
CloverRacer
  • CloverRacer
then pH=-log4.3-log10^(-14) ?
mathmale
  • mathmale
Enclose the argument (4.3 ....) in parentheses. Otherwise you're doing fine. You'll need to evaluate that log. Then, you'll need to negate the value of the log (put a - sign in front of it).
CloverRacer
  • CloverRacer
I'm stuck on evaluating the log -log4.3
CloverRacer
  • CloverRacer
I know -log10^(-14) is just (-14)
mathmale
  • mathmale
You have too many - signs in your expression. Only one of them belongs there. CAn you fix this? As before, evaluate log (..... ) before writing the neg. sign in front of it.
CloverRacer
  • CloverRacer
(-14)?
mathmale
  • mathmale
[H+] is given and is 4.3*10^(-14). 4.3 * 10^(-14) is a product. What is the product rule for logs? True, log 10^(-14) is -14.
CloverRacer
  • CloverRacer
logbAC = logbA + logbC
mathmale
  • mathmale
Yes, that's correct. So, whats the log of the product 4.3 * 10^(-14) ?
CloverRacer
  • CloverRacer
ehh, i'm stumped
mathmale
  • mathmale
What's the log of 4.3? What's the log of 10^(-14)? Whats the log of the product of those two quantities?
CloverRacer
  • CloverRacer
oh wait is it -0.63347?
CloverRacer
  • CloverRacer
for -log4.3
mathmale
  • mathmale
I was hoping you'd evaluate the 2 logs and then add the results together before brining in that negative sign. You have already told me, correctly, that log 10^(-14) is -14. What is the log of 4.3?
CloverRacer
  • CloverRacer
the log of 4.3 is 0.63347 right?
mathmale
  • mathmale
Yes, that looks good. Now, add to gether that 0.63347 and that -14. Can you explain why this is necessary?
mathmale
  • mathmale
Note that one is positive and the other negative.
CloverRacer
  • CloverRacer
would you solve it like log0.63347 * -14
mathmale
  • mathmale
No, you no longer need that "log" operator, because you've already found the logs of 4.3 and 10^(-14).
CloverRacer
  • CloverRacer
ohh okay so it's just 0.63347 * -10?
mathmale
  • mathmale
This isn't multiplication, so throw out that *. Combine (do not multiply) 0.63347 and -14.
mathmale
  • mathmale
* means multiplication + denotes addition
CloverRacer
  • CloverRacer
I got -9.366..
CloverRacer
  • CloverRacer
oh wait careless mistake, now my answer is -13.366..
mathmale
  • mathmale
much better. Now negate that result (multiply it by -1). \
CloverRacer
  • CloverRacer
it is it's reciprocal, 13.3?
mathmale
  • mathmale
No. You have -13.366, which is a negative number, and need only multiply that negative number by -1. what is the result of that? It's true that an EXPONENT of -1 indicates reciprocal in some cases, but not in this one.
CloverRacer
  • CloverRacer
the result of -13.366 * -1 is 13.366?
mathmale
  • mathmale
right, and that's to 3 decimal places. How many decimal places were called for?
CloverRacer
  • CloverRacer
it rounds to 13.4 right?
mathmale
  • mathmale
Right. That's rounded off to the nearest 10th. Your answer? "The approximate pH is ... ?"
CloverRacer
  • CloverRacer
The appoximate pH is 13.4
mathmale
  • mathmale
Right. Very good. Any questins about this procedure?
CloverRacer
  • CloverRacer
Not anymore, thank you so much for your help!
mathmale
  • mathmale
You're welcome. Best of luck to you, and M. C. Bye!

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