anonymous
  • anonymous
graph the equation y-3=-3/2(x+4) Please help
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Zale101
  • Zale101
\(y-y_1=m(x-x_1)\) m is the slope <---you have this given (x1,y1) is the point. <--you have this given
Zale101
  • Zale101
Do you know how to plot a point in a Cartesian graph?
anonymous
  • anonymous
no not really

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Zale101
  • Zale101
Do you know what the term "slope" means?
anonymous
  • anonymous
yes
Zale101
  • Zale101
|dw:1450298177539:dw|
Zale101
  • Zale101
Does this graph look familiar to you?
anonymous
  • anonymous
yes
anonymous
  • anonymous
i need to graph the equation but i do not know how to
Zale101
  • Zale101
Do you know how to plot a point on this graph?
Zale101
  • Zale101
Yes, i'm walking you through on how tog graph on this plane.
Zale101
  • Zale101
Xy-plane
Zale101
  • Zale101
So, in your equation y-3=-3/2(x+4) What is \((x_1,y_1)\)?
anonymous
  • anonymous
yes i know how to plot a point
Zale101
  • Zale101
Okay, good. Let us determine a point from your given equation y-3=-3/2(x+4).
Zale101
  • Zale101
@Hafsahilyas1 By looking at this, \(y-y_1=m(x-x_1)\) and looking at your equation \(y-3=-\frac{3}{2}(x-(-4))\) do you see any similarities?
anonymous
  • anonymous
y1 is 3 and -3/2 is m and -4 ix x1
Zale101
  • Zale101
Perfect. Your point \((x_1,y_1)\) is \((3,-4)\). That's a point on the graph. Can you point \((3,-4)\) on this graph?|dw:1450298642273:dw|
anonymous
  • anonymous
|dw:1450298676829:dw|
Zale101
  • Zale101
Perfect! Now, the next step is really simple. All you have to do is look at your equation \(y-3=-\frac{3}{2}(x-(-4))\) do some algebra steps to solve for y. We want your equation to look like \(y=mx+b\). I'll start doing some few steps and you'll finish it. \(y-3=-\frac{3}{2}(x-(-4))\) \(y-3=-\frac{3}{2}(x+4)\) Then, distribute the -3/2
Zale101
  • Zale101
Can you complete from where i left off?
anonymous
  • anonymous
y-3=-3/2x -6
Zale101
  • Zale101
\(y-3=-\frac{3}{2}x+(-\frac{3}{2}*4))\) \(y-3=-\frac{3}{2}x-\frac{12}{2}\) \(y-3=-\frac{3}{2}x-6\) Perfect, now your last touch is to solve for y, how are you going to do that?
anonymous
  • anonymous
can you help me with this part?
Zale101
  • Zale101
you add 3 to both sides, so the -3 will cancel out or becomes zer0. \(\Large y-3=-\frac{3}{2}x-6\) \(\Large y-3+3=-\frac{3}{2}x-6+3\) \(\Large y+0=-\frac{3}{2}x-6+3\) \(\Large y=-\frac{3}{2}x-6+3\)
Zale101
  • Zale101
\(\Large y=-\frac{3}{2}x-3\)
Zale101
  • Zale101
Do you know what each letter represent in y=mx+b? What does m and b represent?
anonymous
  • anonymous
m represents the points and b represents the slop right?
anonymous
  • anonymous
slope
Zale101
  • Zale101
No. M represent the slope and b represents the y-intercept.
Zale101
  • Zale101
What does y-intercept mean, @Hafsahilyas1 ?
anonymous
  • anonymous
y intercept means that the line croses the y axis
Zale101
  • Zale101
Yes. Y-intercept is when y= # after setting x=0 For example: \(\Large y=mx+b\) When x=0 \(\Large y=m(0)+b\) \(\Large y=0+b\) \(\Large y=b\) So, the point will be when x is zero, y is b \(\large (0,b)\)
Zale101
  • Zale101
Therefore, by doing this, we found another point \((0,b)\)
anonymous
  • anonymous
and b = 3 in my equation so it is (0,3)
Zale101
  • Zale101
Correct. Can you plot \((0,3)\) this here? |dw:1450299794222:dw|
anonymous
  • anonymous
|dw:1450299840575:dw|
anonymous
  • anonymous
this it?
Zale101
  • Zale101
|dw:1450299901305:dw|
anonymous
  • anonymous
|dw:1450300015403:dw|
Zale101
  • Zale101
By the way, are you sure b=3?
anonymous
  • anonymous
yes
anonymous
  • anonymous
no
anonymous
  • anonymous
b= -3
anonymous
  • anonymous
oops
Zale101
  • Zale101
Correct.
Zale101
  • Zale101
|dw:1450300148654:dw|
anonymous
  • anonymous
that the answer
Zale101
  • Zale101
Now, the ultimate last touch is to draw a line crossing the two points and you are done.
anonymous
  • anonymous
|dw:1450300461893:dw| so this is it
Zale101
  • Zale101
Yes.
anonymous
  • anonymous
thanks or the help
Zale101
  • Zale101
No problem.
anonymous
  • anonymous
now i understand how to do these types of problems
Zale101
  • Zale101
I'm glad that you understand them ! :D
anonymous
  • anonymous
bye:)

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