StudyGurl14
  • StudyGurl14
PLEASE HELP! MEDAL!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
StudyGurl14
  • StudyGurl14
can someone do me a favor and screenshot the answer to this? https://answers.yahoo.com/question/index?qid=20111220211214AA6OoAz
tygrr321
  • tygrr321
By adding up the lengths of the fencing, the perimeter is: P = 2y + (x + 3x + x) + 2y + (x + 3x + x) + 2y + 2y + 3x (Note: the length of the base of the larger rectangle is x + 3x + x.) = 13x + 8y. Since the farmer has 1040 yards of fencing: 13x + 8y = 1040. . . . . . . . . . . . . . . . .(i) The area of the entire closure is (5x)(2y) = 10xy. If we solve (i) for y, we can get the area of the closure in terms of x. From (i): y = (1040 - 13x)/8. So, the area of the fence is: A = 10xy = 5x(1040 - 13x)/4. Differentiating dA/dx and setting dA/dx = 0 yields x = 40. Therefore, x = 40 optimizes the area of the enclosure. I hope this helps!
xapproachesinfinity
  • xapproachesinfinity
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StudyGurl14
  • StudyGurl14
thx to you both

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