jmartinez638
  • jmartinez638
Help me with these statements: 1)The definite integral of a polynomial function of odd degree over [-3,3] will __________ be equal to 0. 2)A function f that is continuous on [a,b] and has zeroes at a and b will __________ have a horizontal tangency at some x in (a,b).
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
jmartinez638
  • jmartinez638
These are Always, Sometimes, Never problems.
jmartinez638
  • jmartinez638
If c is a critical number of f and f”(c) = 2, then f _____________ has a point of inflection at x = c.
SolomonZelman
  • SolomonZelman
Think about it... \(\large\color{#000000 }{ \displaystyle F(x)=\int_{-a}^{a} x^{2n+1}dx=\frac{1}{2n+2}x^{2n+2} }\) And then, F(-3)=F(3), because of the symmetry of even power. So, F(3) - F(-3) = 0 HOWEVER, some terms can be \(\large\color{#000000 }{ \displaystyle f(x)=\int_{-a}^{a} x^{2n}dx=\frac{1}{2n+1}x^{2n+1} }\) and this is not necessarily 0

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

SolomonZelman
  • SolomonZelman
I am saying that sometimes it can be a poly with degree 2n+1, and another lesser term x^2n...
SolomonZelman
  • SolomonZelman
there is a test for inflection
SolomonZelman
  • SolomonZelman
let's take some sufficiently small b, let's say b=0.06 So, if f"(c+b) and f"(c-b) have different signs, then concavity indeed changes, and the point x=c is indeed inflection
jmartinez638
  • jmartinez638
Yes.
SolomonZelman
  • SolomonZelman
However, if f"(c+b) and f"(c-b) have same signs then x=c is NOT an inflection.
SolomonZelman
  • SolomonZelman
So your answer would be?
jmartinez638
  • jmartinez638
Sometimes
SolomonZelman
  • SolomonZelman
oh sorry I read f”(c) = 0
SolomonZelman
  • SolomonZelman
if =0 , then c is possibly an inflcetion.
SolomonZelman
  • SolomonZelman
but f”(c) = 2 never an inflcetion at x=c
jmartinez638
  • jmartinez638
O ok
SolomonZelman
  • SolomonZelman
I got to go... (f is concave up at c if f''(c)=2)
jmartinez638
  • jmartinez638
If f(x) < 0 for all \[x \in [a,b], \] then the area between f(x) and x=0 can _____ be accurately calculated with \[\int\limits_{b}^{a} f(x) dx.\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.