anonymous
  • anonymous
A particle moves along the x-axis with a nonconstant acceleration described by a = 12t, where a is in meters per second squared and t is in seconds. If the particle starts from rest so that its speed v and position x are zero when t = 0, where is it located when t = 2 seconds?
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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Astrophysics
  • Astrophysics
You can use calculus right @mathway
Astrophysics
  • Astrophysics
This will require integration note that \[\vec a = \frac{ d^2x }{ dt^2 } = 12t\]
Astrophysics
  • Astrophysics
Or we can use \[a = \frac{ dv }{ dt }\] so \[\int\limits dv = \int\limits 12t dt\]

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anonymous
  • anonymous
I hope so, but this is AP Physics 1, and it is Algebra-based.

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