anonymous
  • anonymous
What are the solutions to the equation x2 + 4x + 5 = 0?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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ShadowLegendX
  • ShadowLegendX
\[x^2 + 4x + 5 = 0\]
anonymous
  • anonymous
do you mind complex solutions?
Astrophysics
  • Astrophysics
Quadratic equation

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ShadowLegendX
  • ShadowLegendX
Use \[b^2 - 4ac\]
Astrophysics
  • Astrophysics
\[\huge x = \frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]
anonymous
  • anonymous
@ShadowLegendX nay, 4 is even, complete the square is quicker
anonymous
  • anonymous
"nah' not ":nay"
Astrophysics
  • Astrophysics
or complete the square haha
ShadowLegendX
  • ShadowLegendX
Well, sometimes formulas are easier for them to remember, especially for tests *shrugs*
anonymous
  • anonymous
saves you from writing the radical in simplest radical form and then dividing properly is all, less like to make an arithmetic mistake
anonymous
  • anonymous
@arielle908 the formula is given to you above try it, if it works great, if not we can walk through competing the square
ShadowLegendX
  • ShadowLegendX
\[4^2 - 4(1)(5)\] Following the formula \[b^2 - 4ac\] With a = 1 b = 4 c = 5 16 - 20 = - 4 From there we just classify where it falls into
ShadowLegendX
  • ShadowLegendX
:)
anonymous
  • anonymous
\[x^2+4x+5=0\] subtract 5 from both sides, what do you get?
ShadowLegendX
  • ShadowLegendX
The answer is not 0 so we know there are two solutions. Also, the answer is negative so we know itʻs complex. Also, -4 is not a perfect square root so we know it is irrational. So we know there are two complex solutions that are irrational in nature. As for the specific solutions, @satellite73 has that part covered :)
anonymous
  • anonymous
"irrational in nature"??
ShadowLegendX
  • ShadowLegendX
two complex conjugates

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