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1) Add 3 to both sides. 2) Use the fact that \(|\)f(x)\(|\)=r, can have two solutions, f(x)=\(\pm\)r
yes, or m-3=-3
if, n-3=3, then n=?
(I mean, m - not n, but you get the point)
and if m-3=-3 then, m=?
So, your two answers/solutions are: m=0 m=6
ohhh okay thanks!
Wait how would I do 1 + |5x - 6| = 47
1) Subtract 1 from both side. This will get you: \(|\)5x-6\(|\)=3 Then, your two solutions are; 5x-6=3 and 5x-6=-3
solve each equation individually and that will give you the two answers.
how did you get 3
oh, 47, I read 4... apologize
CORRECTION *** 1) Subtract 1 from both sides. This will get you: \(|\)5x-6\(|\)=46 Then, your two solutions are; 5x-6=46 and 5x-6=-46
then, solve each equation for x....
alright i see now, thank you!
You are welcome!
@SolomonZelman Hey could you help me on this otherp roblem it's |-4+x| + 7 < 18
You want to isolate absolute value by itself, so what would you do to accomplish this?
hm i'm not sure, i tried subtracting 7 from both sides but that didnt work
subtracting 7 is right .... what did you get after subtracting 7?
oh wait nvm I didn't even subtract 7, lmao i added 7.. wht was i thinking
okay i got it now
sure\( ; ) \)