Ray1998
  • Ray1998
Help please? Will give both fan and medal. Write and graph a direct variation equation that passes through the given point. (5, -6) Thank you in advance!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Nnesha
  • Nnesha
equation for direct variation is \[\rm y=kx\] where k is the constant of variation substitute x and y for the values solve for k (x,y)-->(5,-6)
YumYum247
  • YumYum247
just about what i was thinking!!! LOL good gob neesha!!
Ray1998
  • Ray1998
Okay, thank you. How would I start to solve for K?

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Nnesha
  • Nnesha
show me what did you get after replacing x and y with (5,-6) x=? y=?
Ray1998
  • Ray1998
5 = k(-6) like that?
Nnesha
  • Nnesha
remember (x,y) order pair where first number is x and 2nd one y (5,-6) x= ? y=? remember the alphabetical order
Ray1998
  • Ray1998
5 = x and -6 = y
Nnesha
  • Nnesha
yep right so substitute x for 5 and y for -6
Ray1998
  • Ray1998
y = kx -6 = k(5)
Nnesha
  • Nnesha
looks good to solve for k you should move the number 5 to the opposite side how would you do that ? how would you cancel out 5 from right side ?
Ray1998
  • Ray1998
By multiplying it by itself? That way, the 5 on the right side gets crossed out and then you bring the down while multiplying -6 by 5; which would give you your answer? -6 = k(5) 5 5
Nnesha
  • Nnesha
when you multiply 5 by itself what would you get ?
Ray1998
  • Ray1998
0? Cause they cross out, which makes you drop the k. Right?
YumYum247
  • YumYum247
|dw:1450324757689:dw|
Ray1998
  • Ray1998
Then divide -6 by 5 and get -30
Nnesha
  • Nnesha
hmm no answer my question what would you get when you multiply 5 by itself
Ray1998
  • Ray1998
25
Nnesha
  • Nnesha
right so when you multiply 5 by itself you will get 25 not 0
Ray1998
  • Ray1998
Okay, then what do you do?
Nnesha
  • Nnesha
it's `5 times x` in order to cancel out 5 you should do opposite of multiplication what's the opposite of multiplication ?
Ray1998
  • Ray1998
Division
Nnesha
  • Nnesha
right so divide both side by the number attached to the variable
Ray1998
  • Ray1998
y = kx -6 = k5 5 5 k= -1.2
Nnesha
  • Nnesha
looks good that's k
Ray1998
  • Ray1998
Is that the final answer?
YumYum247
  • YumYum247
you need to write that in equation form......
Nnesha
  • Nnesha
no that's `k` now substitute k with its value y=kx but i suggest u to keep it as fraction -6/5 bec we have to graph the equation
Ray1998
  • Ray1998
-6 = -1.2(5) ?
Nnesha
  • Nnesha
i hope you know the slope intercept form which is y=mx+b where m is the slope and b is the y-intercept
Nnesha
  • Nnesha
no when we write it as equation we should keep the x and y variable
Nnesha
  • Nnesha
y=-1.2x that's it now graph it compare this equation with y=mx+b `m` is slope
Ray1998
  • Ray1998
Yeh, I know it.
Nnesha
  • Nnesha
good :=))
Ray1998
  • Ray1998
Okay, sorry!
Nnesha
  • Nnesha
now just graph it :=))
Nnesha
  • Nnesha
|dw:1450325682273:dw| slope = rise /run that's the reason i said keep it in fraction form so \[\rm y=-\frac{6}{5}x\] the y-intercept in this equation `y=kx` is 0 so our line must pass s through the origin if its doesn't passed through the origin then it's not a direct variation
Nnesha
  • Nnesha
|dw:1450325821178:dw| and and also that's our y-intercept (0) a point where line intersect the y-axis now draw a slope point from y-intercept
Nnesha
  • Nnesha
negative slope = the line should decreasing positive slope = line should increase
Nnesha
  • Nnesha
decrease *
Ray1998
  • Ray1998
Thank you so so much! :) this was really helpful.
Ray1998
  • Ray1998
YOU* were really helpful!
Nnesha
  • Nnesha
np :=))

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