anonymous
  • anonymous
simplify the number using the imaginary unit i
Mathematics
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chestercat
  • chestercat
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anonymous
  • anonymous
\[\sqrt{-9}\]
Nnesha
  • Nnesha
separate the negative sign from number 9\[\large\rm \sqrt{-9}\] can be written |dw:1450328342053:dw| \[\sqrt{-9} \rightarrow \sqrt{9*-1} \rightarrow \sqrt{9}*\sqrt{-1}\]
Nnesha
  • Nnesha
sqrt{-1} equal to what ? do you know ? :=)

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More answers

anonymous
  • anonymous
i?
Nnesha
  • Nnesha
correct i=sqrt{-} and just take the sqrt of 9 that's it
anonymous
  • anonymous
3i
Nnesha
  • Nnesha
looks good
anonymous
  • anonymous
thanks. your the best.
Nnesha
  • Nnesha
yw
anonymous
  • anonymous
i actually have one more, could you help?
anonymous
  • anonymous
@Nnesha
Nnesha
  • Nnesha
will try
anonymous
  • anonymous
\[\sqrt{-48}\]
Nnesha
  • Nnesha
same step first
anonymous
  • anonymous
|dw:1450329162181:dw|
Nnesha
  • Nnesha
look at my drawing -9 is same as -1 times 9 so how what would you write under 2nd sqrt ?
anonymous
  • anonymous
would it also be 1
Nnesha
  • Nnesha
1 times 48 isn't equal to -48
Nnesha
  • Nnesha
48 times what = -48 ?
anonymous
  • anonymous
ohh its -1
Nnesha
  • Nnesha
yes right |dw:1450329738602:dw| and now rewrite 48 as a two numbers (Factors of 48) and one of them must be the perfect square root (48 is not a perfect square root )
anonymous
  • anonymous
|dw:1450330199256:dw|
Nnesha
  • Nnesha
correct now rewrite as a two number (factors) of 48 hmm here is an example sqrt{8} factors of 8 are 1,2,4,8 i have to find the product of which two number will give me 8 and one of them must be the perfect square root 4 is perfect square root and 4 times 2 is 8 so i rewrite\[\sqrt{8}~~as~~\sqrt{2 \times 4} \rightarrow \sqrt{2} *\sqrt{4}\rightarrow 2\sqrt{2}\]

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