anonymous
  • anonymous
Please help! two runners start at opposite ends of a court, one running at 16 km/h and the other at 20 km/h. when they meet their running times total 1 hour. if the slower runner has gone 2 kilometers fewer than the fast runner, how far has the faster runner gone?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
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anonymous
  • anonymous
|dw:1450339669294:dw| I'm not sure how to write an equation
crabbyoldgamer
  • crabbyoldgamer
The easy way to think of this is that they both ran an equal amount of time, because nothing in the problem says anything about one stopping to wait. So they both ran 1/2 hour. D = rt, so for the faster runner D = 20 * 1/2 = 10. For the slower runner D = 16*1/2 = 8. That checks out as far as the slower runner running 2km less,

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crabbyoldgamer
  • crabbyoldgamer
If you're not convinced, go with the full formulas. (f) means fast runner, (s) means slow runner. t(f) + t(s) = 1 so t(s) = 1-t(f) D(f) = 20 * t(f) = D(s) + 2 = 16*(1-t(f)) + 2 D(s) = 16*t(s) 20 * t(f) = 16*(1-t(f)) + 2 20t(f) = 16 - 16t(f) + 2 36t(f) = 18 t(f) = 18/36 = 1/2 D(f) = 20*1/2 = 10 km
anonymous
  • anonymous
Very helpful explanation. Thank you!

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