cmtboy2
  • cmtboy2
Evaluate the expression, using the given value of the variable. 2 – 8x + 3x when x = 5 A. –53 B. –23 C. –15 D.57
Mathematics
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SOLVED
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katieb
  • katieb
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Nnesha
  • Nnesha
substitute x for its value
cmtboy2
  • cmtboy2
the value for x is 5
Nnesha
  • Nnesha
right so replace x with 5

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More answers

cmtboy2
  • cmtboy2
i did
Nnesha
  • Nnesha
show me what did yo uget after replacing x with 5
dakid88
  • dakid88
2 - 8x + 3x x = 5 2 - 8(5) + 3(5) = 2 - 40 + 15 = - 40 + 17 = - 23. (Correct answer B.)
cmtboy2
  • cmtboy2
i did two thing's i did 2 – 85 + 35=-48 and i did 2 – 8.5 + 3.5=4
dakid88
  • dakid88
did u look at wht i posted @cmtboy2
cmtboy2
  • cmtboy2
ya
Nnesha
  • Nnesha
it's 8x `8 times x` so you should multiply the 8 with x value put the parentheses
dakid88
  • dakid88
therefore the answer is B.
cmtboy2
  • cmtboy2
no
dakid88
  • dakid88
no wht
cmtboy2
  • cmtboy2
not you @dakid88
Nnesha
  • Nnesha
so when you replace x for 5 that's how you should write 2-8(5)+3(5) and remember the PEMDAS rule
dakid88
  • dakid88
oh
cmtboy2
  • cmtboy2
oh that i diden't do
cmtboy2
  • cmtboy2
Evaluate the expression, using the given value of the variable. z ÷ 4 – 8z + 2(z – 5) when z = 12 A. –79 B. –74 C. –34 D. 107
cmtboy2
  • cmtboy2
same here right
dakid88
  • dakid88
z ÷ 4 – 8z + 2(z – 5) (12)÷4-8(12) +2((12) -5) =-74
Nnesha
  • Nnesha
stop giving out answer plz
dakid88
  • dakid88
nope im helping him at the same times
Nnesha
  • Nnesha
let him/her learn its not ur knowledge test
Nnesha
  • Nnesha
there is no learning process when u provide the answer as well
cmtboy2
  • cmtboy2
im a boy thank you
dakid88
  • dakid88
lol
dakid88
  • dakid88
like i said im helping him at the same time @Nnesha thank u
cmtboy2
  • cmtboy2
don't you see cmtBOY2
Nnesha
  • Nnesha
there is a difference between helping and enabling
dakid88
  • dakid88
leace me alone were most focus on helping @cmtboy2
Nnesha
  • Nnesha
a girl can use boy word for username
cmtboy2
  • cmtboy2
ok but im a boy
cmtboy2
  • cmtboy2
1 Attachment
cmtboy2
  • cmtboy2
how do you do this
anonymous
  • anonymous
At least try it @cmtboy2, it's the same thing as before. Substitute your variable for your value then simplify.
anonymous
  • anonymous
hey nnesha not cool dude if the guy is a guy cool if ntot cool just live with it kay:)
Nnesha
  • Nnesha
did you understand first question ? if you did then you shouldn't ask that question PEMDAS thats what ur teacher wants u to learn
Nnesha
  • Nnesha
idc if its guy or girl doesn't matter there is a reason i said /him/her its not important to know the gender
anonymous
  • anonymous
@broski532, you literally added nothing to this discussion. If you're not going to help with the question, don't bother answering.
cmtboy2
  • cmtboy2
be nice @tom982
anonymous
  • anonymous
You're joking, right? @Nnesha was doing a great job helping and @broski532 comes in making an issue out of nothing. We're here to help you guys understand maths, not cause unnecessary drama or just post answers.
cmtboy2
  • cmtboy2
am i adding (4)-2 to 12/(4)
Nnesha
  • Nnesha
nice \[\frac{ 12-4 }{ 12 \div 4 }\]
cmtboy2
  • cmtboy2
so i figer them out frist then i add them
cmtboy2
  • cmtboy2
2+3
Nnesha
  • Nnesha
what do you mean *figure them* PEMDAS P) parentheses first E)exponent 3rd MD ) multiply or divide 4th) add or subtract start with the first step is there any parentheses ? no move to the 2nd step is there any exponent ? if no then 3rd step is divide or multiply
Nnesha
  • Nnesha
nvm there is typo
Nnesha
  • Nnesha
\(\color{blue}{\text{Originally Posted by}}\) @Nnesha nice \[\frac{ 12-4 }{ 12 \div 4 }\] \(\color{blue}{\text{End of Quote}}\) i meant \[\frac{ -4-2}{ 12 \div- 4 }\] k value is negative
cmtboy2
  • cmtboy2
-4-2=6
cmtboy2
  • cmtboy2
12/-4=-3
cmtboy2
  • cmtboy2
so now we add (-3) to 6
Nnesha
  • Nnesha
when the sign are the same of both numbers you should just simply add them together and then keep the same sign
Nnesha
  • Nnesha
-4-2= ?
cmtboy2
  • cmtboy2
-6
Nnesha
  • Nnesha
correct \[\frac{ \color{Red}{-4-2 }}{\color{blue}{ 12 \div -4 }}=\frac{\color{reD}{ -6 }}{ \color{blue}{-3} }\] now just simplify that
cmtboy2
  • cmtboy2
now add -6 to -3
Nnesha
  • Nnesha
it's not -6 `+`(-3) fraction = division
cmtboy2
  • cmtboy2
soo divide -3 to -6 right
Nnesha
  • Nnesha
\[\rm \frac{ \top op }{bottom }\] top part divided by the bottom -3/-6 isn't the same as -6/-3
cmtboy2
  • cmtboy2
ok thank
mathstudent55
  • mathstudent55
z ÷ 4 – 8z + 2(z – 5) when z = 12 Answer is not -74

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