anonymous
  • anonymous
State how many imaginary and real zeros the function has.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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dakid88
  • dakid88
Did anyone actually try just factoring it? When I factor I get f(x) = x^2(x+5) + 1(x+5) Now I set f(x) = 0, to find some roots 0 = (x+5)(x^2 + 1)
dakid88
  • dakid88
ok there is no positive root because no change of sign now try this. so \[f \left( -x \right)=-x ^{3+5x ^{2}}-x+5\]

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