At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
Are you solving for x? Or converting to set notation?
Aaahh, I see.~ You simply need to put it in interval notation. So, your answer would be [-3, 0].
and It says I got it wrong
Did you place it in the specified brackets?
(-8x+24) ≤ 16
Do tell me, does it use | or ( ?
the problem uses | but it usually takes ()
|-8x+24| ≤ 16 Thats how it looks on my screen.
Now, remember to use the "  "brackets, because they actually matter. So, your answer would be [1, 5].
Ok that was right. Thanks, but if you don't mind how did you get the answer?
Allow me to write it out for you.~
ok thank you!
Do tell me if that helps! Forgive the long wait. http://puu.sh/lZ1bJ/fae1ccaf64.png
I think...I understood the whole plotting part better in my head. It's meant to be "Plot it!", my bad.~
well uh where did the 1 come from
The brackets indicate that you can only use numbers 1-5. If you were to put in 0, it would be: 24 ≤ 16 <---- Not true, could never happen.
Your maximum x value is 5, so the question you need to ask is.."how low can I go?" In this case, the lowest you can go is 1.
So x would equal 2 in this? |-4x-14|≤6
Actually, it would be -5. I do applaud you on a nice try, though.~
So where did I mess up? I did it like you did it, and I got 2
Oh, I was mixing myself up with another number. When you work it out, you should get: x = -2
|dw:1450367540087:dw| Why wouldn't it equal pos 2? Two negatives make a positive correct?
Since -2 is the highest number, you need to find the lowest number. In this case, it would be -5.
Oh, allow me to show you how I worked it out and why.~
Here is the way it should be worked out. http://puu.sh/lZ2CP/8c3b67fc00.png The reason as to how I removed the negatives is quite simple. The " |, and |" are absolute value bars. Anything in those bars will come out positive. So, all you need to do is remove the negatives.
Ok well hwo do you tell how low you go? ie -5or 1
In order to fully comprehend absolute value type equations, you need to know that there is a positive and negative case. I solved the negative case and the answer came to be -2. When solving the positive case: http://puu.sh/lZ2VH/8be16ce42c.png The answer comes out to be -5.
Oh ok I think I have it now. Thanks so much!
I forgot to flip the sign... http://puu.sh/lZ3b4/fa6e4902e4.png It should look like that!~
Ok cool, I must go due to class change, Thanks again @lvana