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@green_1 can you help me please
Hello, Raven! Which methods of solving systems of linear equations have you used before?
Which system of equations can be used to solve the following problem? Each child ticket for a ride costs $3, while each adult ticket costs $5. If the ride collected a total of $150, and 40 tickets were sold, how many of each type of ticket were sold? Let c be the number of child tickets and a be the number of adult tickets. A. 3a + 5c = 40 a + c = 150 B. 5c +3a =150 c + a = 40 C. 3c + 5a = 150 a + c = 40 D. 3c + 5a = 40 a + c =150
I'd suggest you choose the method most familiar to y ou and then apply it to this particular problem.
that doesn't help me
You have 2 different problems posted. Which do you want to focus on?
the second one the first was answered but the person who answered it deleted their reply
I am trying to find out what you already know. I assume you've solved systems of linear equations before, so that we could use an approach familiar to you to solve the problem at hand.
Among the methods you've probably studied so far are: substution, elimination by addition/subtraction, and graphing. Whic shall we apply to the problem at hand?
can someone else help me?
I stand by the question I've asked y ou: which methods of solving systems of equations have y ou used before? I do that so as to build our discussion on something familiar to you.
If x+y=5, and if 2x-y = 6, the substitution method could be easiest . Solve the 2nd equation for y. Then substitute your expression for y into the first equation.
i'm just getting confused because i have studied a lot but i am behind in class and i forgot how to do it
I'm sorry about that, but that's no excuse for not getting personally involved in solving this problem. Can you do the problem I typed in immediately above, using the substitution method?
did you read the problem? that is not in it at all
The problem I posted was an EXAMPLE posted for the purpose of illustrating the substitution method. If x+y=5, and if 2x-y = 6, the substitution method could be easiest . Solve the 2nd equation for y. Then substitute your expression for y into the first equation. the 2nd equation, 2x-y=6, can be solved for y. y=2x-6. Substitute (2x-6) for y in the first equation. What do you obtain?