anonymous
  • anonymous
Find the experimental probability of getting the letter e when a letter is drawn at random from this text: In English, the letter e appears most frequently among alphabetical characters. In these lines, it appears eighteen times. Note: Exclude spaces and punctuation marks from your analysis. A. 10.00% B. 15.35% C. 17.82% D. 18.20% E. 20.00%
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
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anonymous
  • anonymous
B?
DangerousJesse
  • DangerousJesse
First, can you tell me the number of e's and the total number of letters?
anonymous
  • anonymous
18 E's

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DangerousJesse
  • DangerousJesse
And the rest, including the e's?
mathmale
  • mathmale
all right. 18 e's, out of how many letters total (not including spaces, etc.)?
anonymous
  • anonymous
101?
anonymous
  • anonymous
@DangerousJesse @mathmale
DangerousJesse
  • DangerousJesse
Sorry, had to run it through Python. 101 is correct :)
DangerousJesse
  • DangerousJesse
Solve\18\div101\]Then move the decimal over two spaces to the right.
DangerousJesse
  • DangerousJesse
-_- \[\large\18\div101\]
DangerousJesse
  • DangerousJesse
Not fixing it.
anonymous
  • anonymous
17.82?
DangerousJesse
  • DangerousJesse
Yep :)
mathmale
  • mathmale
If you have 18 letter e's out of 100 letters total, then the prob. of drawing an 'e' is just 18/101. You could leave this answer as is or find the decimal fraction equivalent.
DangerousJesse
  • DangerousJesse
Yeah, the question is asking for the percentage :)
anonymous
  • anonymous
ty :)

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