shanksben12
  • shanksben12
Find the measurement of MN.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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shanksben12
  • shanksben12
just a sec...
shanksben12
  • shanksben12
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shanksben12
  • shanksben12
and the choices...

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shanksben12
  • shanksben12
shanksben12
  • shanksben12
Will medal; fan.
shanksben12
  • shanksben12
.. and follow
shanksben12
  • shanksben12
@parthKohli
shanksben12
  • shanksben12
@ganeshie8
shanksben12
  • shanksben12
@DangerousJesse
shanksben12
  • shanksben12
@Anaise
shanksben12
  • shanksben12
@umermemon9
shanksben12
  • shanksben12
we can both help each other
shanksben12
  • shanksben12
@et1231
shanksben12
  • shanksben12
plz help
DangerousJesse
  • DangerousJesse
First guess?
shanksben12
  • shanksben12
I better at art work, see? (M. C. Escher) XD
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shanksben12
  • shanksben12
2.8---
DangerousJesse
  • DangerousJesse
\[\large(10x+.1)+(7x-.2)=10\]
shanksben12
  • shanksben12
... so that would be the following:(?)\[(10x+.1+.2)+(7x-.2 + .2)=10\]
DangerousJesse
  • DangerousJesse
\[\large17x-.1=10\]
shanksben12
  • shanksben12
1I'm working it out right now...
DangerousJesse
  • DangerousJesse
Add .1 to both sides \[\large17x=10.1\]
DangerousJesse
  • DangerousJesse
Okay :)
shanksben12
  • shanksben12
\[10+.1=10.1(/17=x)\]
DangerousJesse
  • DangerousJesse
No, divide: \[\large10.1\div17\]
DangerousJesse
  • DangerousJesse
Oops wait we're solving for 5.
DangerousJesse
  • DangerousJesse
\[\large(7x+.1)+(10x-.2)=5\]
DangerousJesse
  • DangerousJesse
Simplify \[\large17x-.1=5\]
DangerousJesse
  • DangerousJesse
\[\large.1+5=5.1\]
shanksben12
  • shanksben12
OK so that means that = 17x
DangerousJesse
  • DangerousJesse
\[\large5.1\div17=x\]
DangerousJesse
  • DangerousJesse
Yes, 17x=5.1 :)
shanksben12
  • shanksben12
0.3??????????
shanksben12
  • shanksben12
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DangerousJesse
  • DangerousJesse
Yes, now substitute x with that and check the math, then you can do the math to find MN :)
shanksben12
  • shanksben12
can we work through that?
shanksben12
  • shanksben12
if not, I'm sure I can do it on my own
DangerousJesse
  • DangerousJesse
Sure thing. \[\large(10\times.3-2)+(7\times.3+.1)=\]
shanksben12
  • shanksben12
1 + (2.1 + .1) so that's about 3.1?
DangerousJesse
  • DangerousJesse
\[\large10\times.3=3\]\[\large3-.2=2.8\]
shanksben12
  • shanksben12
thank you; is that the finished equation?
DangerousJesse
  • DangerousJesse
Nope\[\large2.8+(7\times.3+.1)\]\[\large7\times.3=\]
shanksben12
  • shanksben12
2.1
shanksben12
  • shanksben12
2.1?*
DangerousJesse
  • DangerousJesse
And \[\large2.1+.1=\]
shanksben12
  • shanksben12
3.1
DangerousJesse
  • DangerousJesse
No, we're adding .1, not 1
shanksben12
  • shanksben12
2.2?
DangerousJesse
  • DangerousJesse
Yep, and is this true: \[\large2.8+2.2=5\]
shanksben12
  • shanksben12
Thanks! Wow, you really helped... just a sec for medal...
shanksben12
  • shanksben12
;)
DangerousJesse
  • DangerousJesse
So \[\large MN=2.8\] :)

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