anonymous
  • anonymous
I need help with inverses of log functions. I'll put the question below.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Find the inverse of the function. \[\log_{4} x\] I thought it was y=4^x but apparently not?
dr0zier99
  • dr0zier99
no
SolomonZelman
  • SolomonZelman
For example if, \(\color{#000000 }{ \displaystyle r=\log_a(t) }\) Then, \(\color{#000000 }{ \displaystyle a^r=t }\) would be the inverse.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

SolomonZelman
  • SolomonZelman
Another example; \(\color{#000000 }{ \displaystyle \log_{14}{z} =Q\quad \Longrightarrow\quad 14^{Q}=z }\)
anonymous
  • anonymous
Do you think there was a mistake in my practice quiz? y=x^4 is the correct answer, but the base in the log function is 4.
1 Attachment
anonymous
  • anonymous
When you arrive at x=4^y, is there something you have to do to make it y=x^4 instead? Is that it?
SolomonZelman
  • SolomonZelman
\(x=4^y\) is right! But your other options are all wrong (including the one you entered)
SolomonZelman
  • SolomonZelman
\(\color{#000000 }{ \displaystyle \log_4x=y\quad \Longrightarrow \quad 4^y=x }\)
anonymous
  • anonymous
Thank you, I understand now! I think they might be trying to put the answer in the proper exponential form with the x and y having different meanings than before. I'll make sure to ask my teacher.
SolomonZelman
  • SolomonZelman
Yes, ask the instructor:) Good Luck!

Looking for something else?

Not the answer you are looking for? Search for more explanations.