anonymous
  • anonymous
What would be the y-intercepts of the functions y=5^x and y=log5(x)?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
someone please help omg
mathmale
  • mathmale
to find the y-intercept of a function like this, the general approach is to set x= to 0 and find y. Note that this is not true of the log function, but is true of y=5^x. Please evaluate y=5^x when x=0.
AlexandervonHumboldt2
  • AlexandervonHumboldt2
hint: a^0=1

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anonymous
  • anonymous
y=5^0 would be equal to 1
anonymous
  • anonymous
So the y-intercept of y=5^x would be 1?
mathmale
  • mathmale
In regard to \[y=\log_{5} x, \] why don't you graph this function and determine from the graph whether / where a y-intercept exists? To helpers: this question was aimed at @mysterylizard.
mathmale
  • mathmale
Verify that the y-int. of 5^x is 1 by graphing it.
mathmale
  • mathmale
Mystery?
anonymous
  • anonymous
I graphed log5(x) and it kind of looks like it crosses the y-intercept at -1, but I can't tell 100%
mathmale
  • mathmale
Have a graphing calculator? You can look up graphs of many different functions simply by searching the 'Net. Try searching for "log function."
anonymous
  • anonymous
I don't have my graphing calculator with me, so I looked up the graph on the Internet. However, it didn't include exactly where the y-intercept is. I only guessed it was -1 from looking at the graph. Like I said, I'm not sure.
mathmale
  • mathmale
Actually, Mystery, the log function never crosses the y-axis, and thus has no y-intercept. On the other hand, y=x^5 definitely has such an intercept; it is (0,1).
anonymous
  • anonymous
Okay, thank you so much
mathmale
  • mathmale
Please see https://www.google.com/search?q=log+function&espv=2&tbm=isch&imgil=62IQjmNM_jdnlM%253A%253BstAGHl4_xGovmM%253Bhttps%25253A%25252F%25252Fen.wikipedia.org%25252Fwiki%25252FLogarithm&source=iu&pf=m&fir=62IQjmNM_jdnlM%253A%252CstAGHl4_xGovmM%252C_&biw=1360&bih=673&ved=0ahUKEwi2hIWx2ePJAhUX32MKHf25CDQQyjcIKA&ei=PRZzVvbxM5e-jwP986KgAw&usg=__fuc3pLFxVmyreLstt2ASlPlCEWo%3D#imgrc=62IQjmNM_jdnlM%3A&usg=__fuc3pLFxVmyreLstt2ASlPlCEWo%3D You're welcome!!

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