12G
  • 12G
plz help
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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malcolmmcswain
  • malcolmmcswain
:)
12G
  • 12G
Write a proof to show that the diagonals of a parallelogram bisect one another. Be sure to create and name the appropriate geometric figures. This figure does not need to be submitted.
12G
  • 12G
your fast

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malcolmmcswain
  • malcolmmcswain
How many steps do they want?
12G
  • 12G
doesnt say
malcolmmcswain
  • malcolmmcswain
Hmmm... well, this is going to be hard. o-o
malcolmmcswain
  • malcolmmcswain
Ok, so step one. What are we given.
malcolmmcswain
  • malcolmmcswain
Let's make a parrallelogram ABCD. |dw:1450384929769:dw| What do we KNOW right away about this figure?
12G
  • 12G
i found something
malcolmmcswain
  • malcolmmcswain
?
12G
  • 12G
nvm
12G
  • 12G
bisect
malcolmmcswain
  • malcolmmcswain
Ok, so what do we know about parallelogram ABCD?
12G
  • 12G
idk
12G
  • 12G
diagonals of a parallelogram bisect one another?
malcolmmcswain
  • malcolmmcswain
That's what we're trying to prove.
malcolmmcswain
  • malcolmmcswain
Well, if it's a parallelogram, we know that AB and CD are parallel and same with AC and BD
malcolmmcswain
  • malcolmmcswain
Ugh... hold on a second. @AlexandervonHumboldt2 Can you help me, Shurik?
AlexandervonHumboldt2
  • AlexandervonHumboldt2
shuriks here shurik's looking
AlexandervonHumboldt2
  • AlexandervonHumboldt2
|dw:1450314824472:dw|
malcolmmcswain
  • malcolmmcswain
Lol, so what would the next step be? Given AB and CD are parallel.
AlexandervonHumboldt2
  • AlexandervonHumboldt2
|dw:1450314835092:dw|
malcolmmcswain
  • malcolmmcswain
Right...
AlexandervonHumboldt2
  • AlexandervonHumboldt2
|dw:1450314853341:dw|
malcolmmcswain
  • malcolmmcswain
omg lol you are amazing at proofs. I can only do it with guides =[
malcolmmcswain
  • malcolmmcswain
Ok, so let me try to write this out.
12G
  • 12G
is that it?
AlexandervonHumboldt2
  • AlexandervonHumboldt2
|dw:1450315043477:dw|
AlexandervonHumboldt2
  • AlexandervonHumboldt2
as AB=CD, angle ABP=angle DCP and angle APB=angleCPD triangles are congruent
AlexandervonHumboldt2
  • AlexandervonHumboldt2
thus corresponding sides are congruent
AlexandervonHumboldt2
  • AlexandervonHumboldt2
thus AP=PD do the same with other pair of triangles
AlexandervonHumboldt2
  • AlexandervonHumboldt2
|dw:1450315216954:dw|
malcolmmcswain
  • malcolmmcswain
Given: AB and CD are congruent and parallel Given: AC and DB are congruent and parallel Vertical Angles Theorem:
malcolmmcswain
  • malcolmmcswain
I will never be good at proofs ='[
AlexandervonHumboldt2
  • AlexandervonHumboldt2
='[
AlexandervonHumboldt2
  • AlexandervonHumboldt2
@12G got the concept?
12G
  • 12G
i got lost imma reread that again
AlexandervonHumboldt2
  • AlexandervonHumboldt2
ok
12G
  • 12G
AB=CD, angle ABP=angle DCP and angle APB=angleCPD triangles are congruent. corresponding sides are congruent
12G
  • 12G
is that good
AlexandervonHumboldt2
  • AlexandervonHumboldt2
yes
AlexandervonHumboldt2
  • AlexandervonHumboldt2
in the end add that they bisect and that AP=.....
12G
  • 12G
AP=PD that ?
12G
  • 12G
hello

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