calculusxy
  • calculusxy
How can I easily know whether I can factor from before (even without doing it)? And is it possible to do it?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
phi
  • phi
not easily. The only "clue" is if it's on a test and the numbers are reasonably small, it probably is factorable. In the real world, you would use a computer to figure things out.
anonymous
  • anonymous
You can use the discriminant of a quadratic equation in order to determine if the equation is "prime." Equations that are not prime may be factored, whereas prime ones cannot be factored (and then you'll have to use the quadratic formula to solve for your variable(s). Quadratic Equation: \[ax^2 + by^2 + c \] Discriminant: \[b^2 - 4ac\] If you get a negative discriminant value (discriminant < 0), the equation is prime and not factorable.
anonymous
  • anonymous
To clarify, a negative discriminant means that you have no "real" roots, but imaginary roots are still possible.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Sorry I meant \[ax^2 + bx^2 + c\]
calculusxy
  • calculusxy
i have the equation \(-6p^2 - 17p - 56\) if i do use the discriminant, i would have \(b^2 - 4ac = -17^2 - 4(-6)(-56)\) \(289 - 1344\) it will be a negative, so it's prime. right?
phi
  • phi
a negative discriminant means the factors are complex (have an imaginary number in them). That usually means no solution (though sometimes in physics, we can make sense of a complex number)
calculusxy
  • calculusxy
Thank you!

Looking for something else?

Not the answer you are looking for? Search for more explanations.