matlee
  • matlee
Precaluclus need help will give owl bucks most needed help for test tommorow
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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matlee
  • matlee
A=70 , a=7 , b=4 ; B=?
matlee
  • matlee
For each traingle, determine the indicated value
rishavraj
  • rishavraj
here apply the sine rule.....It says \[\frac{ a }{ \sin A } = \frac{ b }{ \sin B }\]

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rishavraj
  • rishavraj
According to sine rule \[\frac{ a }{ \sin A } =\frac{ b }{ \sin B } = \frac{ c }{ \sin C }\]
matlee
  • matlee
Hello sorry had to get something
matlee
  • matlee
How do u know which one is which rules , is there a easier way to know like the letter itself or only the phrases state that its possible
rishavraj
  • rishavraj
The sine rule is used when we are given either a) two angles and one side, or b) two sides and a non-included angle.... and u see if u even try to apply cosine rule .....u dont have the value of 'c'....so in the cosine rule u will be having two variables
matlee
  • matlee
O sorry i wrote it wrong
matlee
  • matlee
Im trying to find the pcitrue
matlee
  • matlee
matlee
  • matlee
They included an angle so would it still be the sine rule
rishavraj
  • rishavraj
yup....... :)
matlee
  • matlee
Ok so now i shall find the sine rule
matlee
  • matlee
nvm u wrote it
rishavraj
  • rishavraj
yup use the equation \[\frac{ a }{ \sin A } = \frac{ b }{ \sin B }\] or u can say \[\frac{ \sin A }{ a } = \frac{ \sin B }{ b }\] u got the value of a,b,A get the value of sinA using calculator
matlee
  • matlee
|dw:1450398125463:dw|
rishavraj
  • rishavraj
yup
matlee
  • matlee
9.04520517796
rishavraj
  • rishavraj
whts tht???
matlee
  • matlee
7/sin70
rishavraj
  • rishavraj
ooo yeahh
matlee
  • matlee
so what nowlol
rishavraj
  • rishavraj
see on plugging the value of sinA \[\frac{ 7 }{ 0.9396926208 } = \frac{ 4 }{ \sin B }\] then u can write it as \[\frac{ 0.9396926208 }{ 7 } = \frac{ \sin B }{ 4 }\] so sin B/4 = 0.134241
rishavraj
  • rishavraj
so sin B = 0.536972 and B = \[\sin^{-1} (0.134241)\] use calculator to get B
matlee
  • matlee
what but i dived 7 over sinA already but sina still exists? just to confirm
rishavraj
  • rishavraj
plug the value of sin A sin A = 0.9396926208
rishavraj
  • rishavraj
like 7/sin A = 7/0.9396926208 = 7.45
rishavraj
  • rishavraj
so 7.45 = 4/sinB
matlee
  • matlee
for sin70 i got 0.77389068155
rishavraj
  • rishavraj
nah nah sin 70 = 0.93969
matlee
  • matlee
Ok google was lieing to me i jsut saw the actual answer
matlee
  • matlee
So why do i do sin-1?
rishavraj
  • rishavraj
\[B = \sin^{-1} (0.5369)\]
matlee
  • matlee
So in a caluclator i would put X instead of B?
rishavraj
  • rishavraj
if u r using calculator on computer..then type 0.5369 and click on sin-1
matlee
  • matlee
\[7=\sin b/4\]
rishavraj
  • rishavraj
hmmmm wht?????/ it supposed to be \[\frac{ \sin 70 }{ 7 } = \frac{ \sin B }{ 4 }\]
rishavraj
  • rishavraj
the value of sin 70 = 0.93969 so sin 70/7 = 0.13424 so \[\frac{ \sin B }{ 4 } = 0.13424\]
matlee
  • matlee
i mean 7.45=sinb/4?
rishavraj
  • rishavraj
7.45 = 4/sin B
matlee
  • matlee
Ok, so what od i do after now why do i pull out sinb-1?
rishavraj
  • rishavraj
\[B = \sin^{-1} (0.5369)\] using calculator B = 32.47 approx
matlee
  • matlee
Why do you use sin-1
rishavraj
  • rishavraj
hmmmm u see if x = sin A then \[A = \sin^{-1} x\]
matlee
  • matlee
omg ur making me cry where u get the X from
rishavraj
  • rishavraj
lol I used tht expression to make u understand why i used sin-1
rishavraj
  • rishavraj
so in ur case x = 0.5369 so sin B = 0.5369 \[B = \sin^{-1} 0.5369\]
matlee
  • matlee
Ok i need to write this ona test and show work. But if she asks me what is Sin-1 there for i will not know. idk where 0.5369 because in my calc it says sin-1= -0.841 also i need to use calc on the test will not be ablue to use comp
matlee
  • matlee
1 Attachment
rishavraj
  • rishavraj
see the overall solution is \[\frac{ a }{ \sin A } = \frac{ b }{ \sin B }\] \[\frac{ 7 }{ \sin 70 } = \frac{ 4 }{ \sin B }\] \[\frac{ 7 }{ 0.93969 } = \frac{ 4 }{ \sin B }\] \[7.45 = \frac{ 4 }{ \sin B }\] \[\frac{ 7.45 }{ 4 } = \frac{ 1 }{ \sin B }\] \[1.8625 = \frac{ 1 }{ \sin B }\] \[\sin B = \frac{ 1 }{ 1.8625 }\] \[\sin B = 0.5369\]
rishavraj
  • rishavraj
so now to get B... \[B = \sin^{-1} 0.5369\]
matlee
  • matlee
Ok thank you! That so much better to udnerstand i just have 1 question
matlee
  • matlee
How do u get the 4 over to the bottom of 7.45?
rishavraj
  • rishavraj
u know \[\frac{ a }{ b } = c\] a = bc or \[2x = 3\] then \[x =\frac{ 3 }{ 2 }\] jst an example
matlee
  • matlee
yes but i thought if u divide 4 u have to divide by both sided which will mean u divide 4 by sinB too
rishavraj
  • rishavraj
\[\frac{ 4 }{ \sin B } \times \frac{ 1 }{ 4 } = \frac{ 1 }{ \sin B }\]
matlee
  • matlee
i give up
rishavraj
  • rishavraj
lol u shouldnt.... see tell me whts the value of \[\frac{ 4 }{ 3 } \times \frac{ 1 }{ 4 }\]
matlee
  • matlee
5/12
matlee
  • matlee
i ean 4/12
rishavraj
  • rishavraj
hmmm how ????? dont u think 4 would cancel out ??? and answer would be 1/3?????
rishavraj
  • rishavraj
as 4/4 = 1
matlee
  • matlee
1/3 yes
rishavraj
  • rishavraj
thts the reason for \[\frac{ 4 }{ \sin B } \times \frac{ 1 }{ 4 } = \frac{ 1 }{ \sin B }\]
matlee
  • matlee
O yes but thata little bit weird, did you cross multiply
rishavraj
  • rishavraj
yup u can say tht
matlee
  • matlee
but then would it be 7.45(sinb)=4
rishavraj
  • rishavraj
yup obviously ...then next step is sin B = 4/7.45 u get tht???
matlee
  • matlee
no
matlee
  • matlee
wait yes i got it but i dont see how it got there
matlee
  • matlee
@satellite73 helpp, i have 2 questions
matlee
  • matlee
1 Attachment
matlee
  • matlee
@satellite73 i want to give him owl bucks but it says i dont have enough i have 9 owl bucks helpp
matlee
  • matlee
Im confused cus u multipled 1 side oh thats what it was u forgot to write the step for dividing. I cant think as fast as you sorry!!!

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