nicoleg7
  • nicoleg7
Rita is writing statements as shown to prove that if segment ST is parallel to segment RQ, then x = 24. Statement 5. (2x + 28):95 = Corresponding sides of similar triangles are in proportion Which of the following can she use to complete statement 5? A) 28:95 B) 28:35 C) 60:95 D) 60:35
Geometry
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SOLVED
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schrodinger
  • schrodinger
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nicoleg7
  • nicoleg7
nicoleg7
  • nicoleg7
what goes after the equal sign for the statement corresponding sides of similar triangles are in proportion to be true
jim_thompson5910
  • jim_thompson5910
what do you notice about `2x + 28` ? Do you see how it's found by combining the lengths of QS and PS ?

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nicoleg7
  • nicoleg7
yes
jim_thompson5910
  • jim_thompson5910
so PQ = 2x+28 similarly, PR = 95 since PT = 35 TR = 60 PT+TR = 35+60 = 95 = PR
nicoleg7
  • nicoleg7
is it d
jim_thompson5910
  • jim_thompson5910
|dw:1450405330756:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1450405389327:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1450405407731:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1450405430630:dw|
jim_thompson5910
  • jim_thompson5910
so \[\Large (2x+28):95\] is the ratio \[\Large \text{PQ}:\text{PR}\]
jim_thompson5910
  • jim_thompson5910
make sense?
nicoleg7
  • nicoleg7
I think so its A
jim_thompson5910
  • jim_thompson5910
why A?
nicoleg7
  • nicoleg7
since pq is equal to pr I guess 95 is equal to 28 idk
nicoleg7
  • nicoleg7
was I right :/
jim_thompson5910
  • jim_thompson5910
no, but here is another ratio |dw:1450405768957:dw|
jim_thompson5910
  • jim_thompson5910
So, \[\Large \text{PQ}:\text{PR}=\text{PS}:\text{PT}\] \[\Large (2x+28):95=28:35\]
nicoleg7
  • nicoleg7
thxs lol im not good at geometry @jim_thompson5910
jim_thompson5910
  • jim_thompson5910
no problem
nicoleg7
  • nicoleg7
very good teacher tho thxs for explaining I got it now

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