edbf123
  • edbf123
i need help with a lot of questions i literally have no clue what to do
Geometry
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
edbf123
  • edbf123
1 Attachment
edbf123
  • edbf123
this is the first two
NeverEndingCycle
  • NeverEndingCycle
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edbf123
  • edbf123
both
edbf123
  • edbf123
so i know how to do it in the future
NeverEndingCycle
  • NeverEndingCycle
I'll let the professor do it XD
zepdrix
  • zepdrix
|dw:1450405325789:dw|
zepdrix
  • zepdrix
These are all quadrilaterals. Are they all squares?
edbf123
  • edbf123
no
zepdrix
  • zepdrix
Ok good, that cancels out option B, we've determined that all quadrilaterals are NOT necessarily squares.
zepdrix
  • zepdrix
Are they all rectangles? :)
edbf123
  • edbf123
no but they are all parallelograms?
zepdrix
  • zepdrix
Yes, all the ones I drew are parallelograms, my mistake :) Lemme draw ANOTHER quadrilateral.
zepdrix
  • zepdrix
|dw:1450405485531:dw|
zepdrix
  • zepdrix
That new shape is still a quadrilateral (4-sided figure). But it's not a parallelogram. So if it's a quadrilateral, it's not necessarily a parallelogram, ya? :)
edbf123
  • edbf123
yeah so then it would be c ?
zepdrix
  • zepdrix
Good, yes. Option C: All rectangles are `quadrilaterals` basically is saying this: All rectangles `have 4 sides`.
edbf123
  • edbf123
i see lol
edbf123
  • edbf123
k next one
zepdrix
  • zepdrix
k sec, reading >.<
zepdrix
  • zepdrix
|dw:1450405799077:dw|Here is an example of a specific quadrilateral, a Rhombus. All the side lengths are equal, and the diagonals bisect one another (intersect at the middle of their length).
zepdrix
  • zepdrix
So this shows us that option A is not sufficient. We have the side lengths equal, we have diagonals bisected, but we didn't end up with a square.
zepdrix
  • zepdrix
Will any of the other options work >.< hmm thinking
edbf123
  • edbf123
c maybe
zepdrix
  • zepdrix
|dw:1450406084898:dw|What would happen if we were to stretch out one of these diagonals so they were the same length?
zepdrix
  • zepdrix
|dw:1450406156699:dw|I drew it a little sloppy lol But we should end up with a square, ya? The diagonals being equal length, and all other sides being equal length forces the diagonals to bisect perpendicularly (at right angles).
zepdrix
  • zepdrix
I guess option B is what we were looking for :) But hmm that one is tricky.
zepdrix
  • zepdrix
I shoulda let Cycle help you, Geometry is not really my thing XD lol
edbf123
  • edbf123
yeah thanks tho help me with a few more?
zepdrix
  • zepdrix
Bahhh I need a Geometry break XD @NeverEndingCycle
edbf123
  • edbf123
k thanks
edbf123
  • edbf123
lol
edbf123
  • edbf123
1 Attachment
jim_thompson5910
  • jim_thompson5910
If a quadrilateral has 4 equal sides, then it is a rhombus If a quadrilateral is a parallelogram with equal diagonals, then it is a rectangle if a figure is a rhombus and a rectangle, then it must be a square
jim_thompson5910
  • jim_thompson5910
think of it in terms of venn diagrams |dw:1450408037282:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1450408060867:dw|
edbf123
  • edbf123
i already have that one i need the one i just posted
jim_thompson5910
  • jim_thompson5910
it's a rectangle, so the diagonals are equal KM = LN 6x+16 = 49 x = ??
edbf123
  • edbf123
oh lol 49
edbf123
  • edbf123
right?
jim_thompson5910
  • jim_thompson5910
no
edbf123
  • edbf123
i dont know im confused i suck at this
jim_thompson5910
  • jim_thompson5910
you need to isolate x in `6x+16 = 49`
edbf123
  • edbf123
-16 on both sides?
jim_thompson5910
  • jim_thompson5910
yep, then divide both sides by 6
edbf123
  • edbf123
so 5.5?
jim_thompson5910
  • jim_thompson5910
correct
edbf123
  • edbf123
cool help me with a few more
jim_thompson5910
  • jim_thompson5910
I'll help with one more
edbf123
  • edbf123
1 Attachment
edbf123
  • edbf123
wait wrong one
edbf123
  • edbf123
1 Attachment
jim_thompson5910
  • jim_thompson5910
since the two horizontal sides are parallel, we know that the same side interior angles are supplementary that means `a+36 = 180` and `113+b = 180`
edbf123
  • edbf123
thank you
jim_thompson5910
  • jim_thompson5910
no problem

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