Questions Asked

agillogly:
Group Title
Use the law of cosines to find the value of 2*4*5 cos theta
a 40
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 updated 2 years ago
 No Medals Yet

agillogly:
Group Title
if sin x co(pi/7)sin(pi/7)cos x= sqrt2/2
then x can equal ____ check all that apply.
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 updated 2 years ago
 2 replies
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agillogly:
Group Title
cos(a/2)=+ sqrt 1+cosa/2 for all values of a
true or false?
 updated 2 years ago
 3 replies
 No Medals Yet

agillogly:
Group Title
cos(ab)=cos a cos b + sin a sin b
for all values of a and b
true or false?
 updated 2 years ago
 4 replies
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agillogly:
Group Title
cos(x)=cos x for all values of x
ture or false?
 updated 2 years ago
 3 replies
 3 Medals

agillogly:
Group Title
Someone help! Please.
 pi/3 cos pi/6 = ½(sin pi/2+sin pi/6)
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 updated 2 years ago
 23 replies
 1 Medal

agillogly:
Group Title
Use the squared identities to simplify
2cos^2x cos^2x
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 updated 2 years ago
 4 replies
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agillogly:
Group Title
csc(6x)cot(x)/csc(6x)+cot(6x) =
 updated 2 years ago
 5 replies
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agillogly:
Group Title
sin(75°)=√1cos(150°)/2
true or false?
 updated 2 years ago
 6 replies
 1 Medal

agillogly:
Group Title
cos(x/5) sin(x/5)=½[sin(2x/5)]
true or false?
 updated 2 years ago
 14 replies
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agillogly:
Group Title
cos x cos y = ½(sin(x+y)+sin(xy))
true or false?
 updated 2 years ago
 3 replies
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agillogly:
Group Title
Which of the following is an identity?
a tan^2x+cos^2x=1
b(12sin^2x)csc^2x=4cos^2x2
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 updated 2 years ago
 1 reply
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agillogly:
Group Title
the value pi/4 is a solution for the equation 3 sqrt2 sec theta +7 =1
true or false?
 updated 2 years ago
 5 replies
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agillogly:
Group Title
Solve on the interval [0,2pi) :
2 csc x 3 = 5
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 updated 2 years ago
 8 replies
 1 Medal

agillogly:
Group Title
SOLVE cos(x)(cos x+1)=0
a x=pi/3 + 2pi n, x=3pi/4 + 2pi n
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 updated 2 years ago
 3 replies
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agillogly:
Group Title
which of the functions have peroid pi check all that apply
y= cot x
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 updated 2 years ago
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agillogly:
Group Title
if the point p (3/5, y) lies on the unit circle and P is in the second quadrant, what does y equal?
 updated 2 years ago
 5 replies
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