Questions Asked

bakerla5:
help needed, can someone tackle this problem
If g(x) = x2 + 10x with x ≥ −5, find g^1(75)
 updated 6 months ago
 2 replies
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bakerla5:
can someone solve this
8x^218x81=0
 updated 7 months ago
 1 reply
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bakerla5:
please factor
x^2+3x+9/4=5/4
 updated 7 months ago
 1 reply
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bakerla5:
find all real solutions
x^2+3x+1=0
 updated 7 months ago
 1 reply
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bakerla5:
what is the process in finding the least common denominator in this problem?
1/(t1)+t/(7t2)=1/7
 updated 7 months ago
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bakerla5:
solve the equation
8/x=5/4x+1
 updated 7 months ago
 22 replies
 1 Medal

bakerla5:
evaluate (16x7)/(8x+3)=23/x
 updated 7 months ago
 1 reply
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bakerla5:
Solve the Equation
1/(x1)+6/(x+1)=8/(x^21)
 updated 7 months ago
 12 replies
 1 Medal

bakerla5:
can someone help me with this problem. Solve the equation.
6/(x+1)1/3=1/2x+2
…
 updated 8 months ago
 2 replies
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bakerla5:
how would i interpret this function to graph
y = 7 − 3f(x)
 updated one year ago
 2 replies
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bakerla5:
can some one help me with the following function problem which i find challenging.
A function is given. Determine the average rate of cha…
 updated one year ago
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bakerla5:
A function is given. Determine the average rate of change of the function between the given values of the variable.
f(x) = 6 − x2; x = 2…
 updated one year ago
 4 replies
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bakerla5:
how do i go about this problem below?
The average rate of change of the linear function f(x) = 6x + 3 between any two points is
 updated one year ago
 4 replies
 1 Medal

bakerla5:
If you travel 200 miles in two hours, then your average speed for the trip is
average speed = (200)/()=[] miles per hr
 updated one year ago
 2 replies
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bakerla5:
can some one help me with steps to solve this problem? {5/(a+h)+4)(5)/(a+4)}/h
 updated one year ago
 5 replies
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bakerla5:
Find f(a), f(a + h), and the difference quotient
Find f(a), f(a + h), and the difference quotient
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 updated one year ago
 2 replies
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bakerla5:
Hi, can anyone give some advise on how to do functions, particularly difference quotient?
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 updated one year ago
 1 reply
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