sabika13
Name:
Sabika Mirza
School:
About:
Mercy Upon Mankind
Savior Of All Mankind
- Yah Hussien ♥
'Death with dignity is better then life with humiliation'
sabikafathima@hotmail.com
http://www.formspring.me/sabikamirza
Twitter: Sabika13 ill follow backk :)
I love my nephew Reza<3
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Questions Asked 49
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Questions Asked 1
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Medals Received 0
Questions Asked 2
Questions Answered 0
Medals Received 0
Questions Asked 49
Questions Answered 8
Medals Received 3
0
Questions Asked
sabika13:
Group Title
solve for x : 2(sin^4x + cos^4x) = 1
updated 2 years ago
No Medals Yet
Mathematics
sabika13:
Group Title
solve for x in the given interval
2tanx=secx (-2pi,0)
updated 2 years ago
2 replies
No Medals Yet
Mathematics
sabika13:
Group Title
solve for x in the given interval sqrt2sinx+tanx=0 (-pi,pi)
updated 2 years ago
24 replies
1 Medal
Mathematics
sabika13:
Group Title
solve for x in the given interval
sinxtan3x=0(-pi,0)
updated 2 years ago
3 replies
No Medals Yet
Mathematics
sabika13:
Group Title
solve for x in the given interval: sinx-sinxtanx=0 (0,pi)
updated 2 years ago
No Medals Yet
Mathematics
sabika13:
Group Title
Find the points of intersection of each pair of curves in the given interval.
i) y=sin2x, y=sinx
updated 2 years ago
10 replies
No Medals Yet
Mathematics
sabika13:
Group Title
How do I prove this: (secx-cosx)(cscx-sinx)=tanx/(1+tan^2x)
updated 2 years ago
6 replies
No Medals Yet
Mathematics
sabika13:
Group Title
Write an equation this is equivalent to f(x)=-5sin(x-pi/2) - 8 using trig.function of x
updated 2 years ago
9 replies
No Medals Yet
Mathematics
sabika13:
Group Title
How do I solve this using trig identities: tan(pi/4 + x) +tan(pi/4 - x) =2sec2x
updated 2 years ago
27 replies
No Medals Yet
Mathematics
sabika13:
Group Title
How do I solve this trig identity: cos2x/(1+sinx^2)=tan(pie/4 -x)
updated 2 years ago
27 replies
2 Medals
Mathematics
sabika13:
Group Title
How do I prove this Identity: (tanx/secx-1)+(tanx/secx+1)=(2sinxcosx)/(cos^2x(1-cosx) - 4/(2sinxcosx)
updated 2 years ago
No Medals Yet
Mathematics
sabika13:
Group Title
how do prove this identity: sin^4x -cos^4x=1-2cos^2x
updated 2 years ago
30 replies
1 Medal
Mathematics
sabika13:
Group Title
how do prove this identity: sin^4x -cos^4x=1-2cos^2x
updated 2 years ago
4 replies
1 Medal
Mathematics
sabika13:
Group Title
How do I prove this using trig identity: 1/(1+sinx) = sec^2x-tanx/cosx
updated 2 years ago
No Medals Yet
Mathematics
sabika13:
Group Title
How do I prove this by using trig identities: (2sin^2x-1)/(sinxcosx)/=tanx-cotx
updated 2 years ago
12 replies
5 Medals
Mathematics
sabika13:
Group Title
how do i prove this using trig identity: (2sinx+3cosx)^2+(3sinx-2cosx)^2=13
updated 2 years ago
6 replies
No Medals Yet
Mathematics
sabika13:
Group Title
How do I solve this using identity:
cos^2x/(1+2sinx-3sin^2x) = (1+sinx)/(1+3sinx)
updated 2 years ago
7 replies
2 Medals
Mathematics
sabika13:
Group Title
How i know what cofunction identities to use for the trigonometric identities featuring pie/2.. like if i get a question like cos4pie/3 .. h…
updated 2 years ago
No Medals Yet
Mathematics
sabika13:
Group Title
prove this identity: (sinx+tanx)/(cosx+1)=tanx
updated 2 years ago
12 replies
1 Medal
Mathematics
sabika13:
Group Title
Given that sin pie/6 = 1/2, use an equivalent trigonometric expression to show that cos= 1/2. I have no clue how to do this, can someone hel…
updated 2 years ago
14 replies
2 Medals
Mathematics
sabika13:
Group Title
Lynda is flying her kite at the end of 40-m string. The string makes an angle of pie/4 with the ground. the wind speed increases, andthe kit…
updated 2 years ago
4 replies
1 Medal
Mathematics
sabika13:
Group Title
How do you find the horizontal asymptote.. It says in my textbook that " to find horizontal asymptote divide numerator and denominator by x …
updated 2 years ago
9 replies
3 Medals
Mathematics
sabika13:
Group Title
When they work together, Stuart and Lucy can deliver flyers to all the hokes in their neighbourhood in 42 min. When Lucy works alone, she ca…
updated 2 years ago
5 replies
1 Medal
Mathematics
sabika13:
Group Title
the population,p, of frogs in a newly created conservation arra is modelled by p(t) = 50+ (2500t^2) / (25+t^2)
updated 2 years ago
No Medals Yet
Mathematics
sabika13:
Group Title
for the functions f(x)= 2x/(x-3), compare the slopes of the tangents
i) at the points where x=3.5 and x=20
how do i do this?
updated 2 years ago
25 replies
1 Medal
Mathematics
sabika13:
Group Title
I need some serious help please :(..
Make a summary table with these headings shown for each graph: Interval, Sign of Function, Sign of Slo…
updated 2 years ago
18 replies
1 Medal
Mathematics
sabika13:
Group Title
I need some serious help please :(..
Make a summary table with these headings shown for each graph: Interval, Sign of Function, Sign of Slo…
updated 2 years ago
1 reply
No Medals Yet
Mathematics
sabika13:
Group Title
Has anyone read Handmaids tale? Can someone help me out!
updated 2 years ago
No Medals Yet
Mathematics
sabika13:
Group Title
How do I factor this: 16(x+1)^3 +2?
updated 2 years ago
6 replies
No Medals Yet
Mathematics
sabika13:
Group Title
450 = x(18-x)(20-2x) How do I solve this??
updated 2 years ago
3 replies
1 Medal
Mathematics
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