sabika13
Name:
Sabika Mirza
School:
About:
Mercy Upon Mankind
Savior Of All Mankind
- Yah Hussien ♥
'Death with dignity is better then life with humiliation'
sabikafathima@hotmail.com
http://www.formspring.me/sabikamirza
Twitter: Sabika13 ill follow backk :)
I love my nephew Reza<3
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Questions Asked 49
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Questions Asked 1
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Medals Received 0
Questions Asked 2
Questions Answered 0
Medals Received 0
Questions Asked 49
Questions Answered 8
Medals Received 3
0
Questions Asked
sabika13:
Group Title
solve for x : 2(sin^4x + cos^4x) = 1
updated one year ago
No Medals Yet
Mathematics
sabika13:
Group Title
solve for x in the given interval
2tanx=secx (-2pi,0)
updated one year ago
2 replies
No Medals Yet
Mathematics
sabika13:
Group Title
solve for x in the given interval sqrt2sinx+tanx=0 (-pi,pi)
updated one year ago
24 replies
1 Medal
Mathematics
sabika13:
Group Title
solve for x in the given interval
sinxtan3x=0(-pi,0)
updated one year ago
3 replies
No Medals Yet
Mathematics
sabika13:
Group Title
solve for x in the given interval: sinx-sinxtanx=0 (0,pi)
updated one year ago
No Medals Yet
Mathematics
sabika13:
Group Title
Find the points of intersection of each pair of curves in the given interval.
i) y=sin2x, y=sinx
updated one year ago
10 replies
No Medals Yet
Mathematics
sabika13:
Group Title
How do I prove this: (secx-cosx)(cscx-sinx)=tanx/(1+tan^2x)
updated one year ago
6 replies
No Medals Yet
Mathematics
sabika13:
Group Title
Write an equation this is equivalent to f(x)=-5sin(x-pi/2) - 8 using trig.function of x
updated one year ago
9 replies
No Medals Yet
Mathematics
sabika13:
Group Title
How do I solve this using trig identities: tan(pi/4 + x) +tan(pi/4 - x) =2sec2x
updated one year ago
27 replies
No Medals Yet
Mathematics
sabika13:
Group Title
How do I solve this trig identity: cos2x/(1+sinx^2)=tan(pie/4 -x)
updated one year ago
27 replies
2 Medals
Mathematics
sabika13:
Group Title
How do I prove this Identity: (tanx/secx-1)+(tanx/secx+1)=(2sinxcosx)/(cos^2x(1-cosx) - 4/(2sinxcosx)
updated one year ago
No Medals Yet
Mathematics
sabika13:
Group Title
how do prove this identity: sin^4x -cos^4x=1-2cos^2x
updated one year ago
30 replies
1 Medal
Mathematics
sabika13:
Group Title
how do prove this identity: sin^4x -cos^4x=1-2cos^2x
updated one year ago
4 replies
1 Medal
Mathematics
sabika13:
Group Title
How do I prove this using trig identity: 1/(1+sinx) = sec^2x-tanx/cosx
updated one year ago
No Medals Yet
Mathematics
sabika13:
Group Title
How do I prove this by using trig identities: (2sin^2x-1)/(sinxcosx)/=tanx-cotx
updated one year ago
12 replies
5 Medals
Mathematics
sabika13:
Group Title
how do i prove this using trig identity: (2sinx+3cosx)^2+(3sinx-2cosx)^2=13
updated one year ago
6 replies
No Medals Yet
Mathematics
sabika13:
Group Title
How do I solve this using identity:
cos^2x/(1+2sinx-3sin^2x) = (1+sinx)/(1+3sinx)
updated one year ago
7 replies
2 Medals
Mathematics
sabika13:
Group Title
How i know what cofunction identities to use for the trigonometric identities featuring pie/2.. like if i get a question like cos4pie/3 .. h…
updated one year ago
No Medals Yet
Mathematics
sabika13:
Group Title
prove this identity: (sinx+tanx)/(cosx+1)=tanx
updated one year ago
12 replies
1 Medal
Mathematics
sabika13:
Group Title
Given that sin pie/6 = 1/2, use an equivalent trigonometric expression to show that cos= 1/2. I have no clue how to do this, can someone hel…
updated one year ago
14 replies
2 Medals
Mathematics
sabika13:
Group Title
Lynda is flying her kite at the end of 40-m string. The string makes an angle of pie/4 with the ground. the wind speed increases, andthe kit…
updated one year ago
4 replies
1 Medal
Mathematics
sabika13:
Group Title
How do you find the horizontal asymptote.. It says in my textbook that " to find horizontal asymptote divide numerator and denominator by x …
updated one year ago
9 replies
3 Medals
Mathematics
sabika13:
Group Title
When they work together, Stuart and Lucy can deliver flyers to all the hokes in their neighbourhood in 42 min. When Lucy works alone, she ca…
updated one year ago
5 replies
1 Medal
Mathematics
sabika13:
Group Title
the population,p, of frogs in a newly created conservation arra is modelled by p(t) = 50+ (2500t^2) / (25+t^2)
updated one year ago
No Medals Yet
Mathematics
sabika13:
Group Title
for the functions f(x)= 2x/(x-3), compare the slopes of the tangents
i) at the points where x=3.5 and x=20
how do i do this?
updated one year ago
25 replies
1 Medal
Mathematics
sabika13:
Group Title
I need some serious help please :(..
Make a summary table with these headings shown for each graph: Interval, Sign of Function, Sign of Slo…
updated one year ago
18 replies
1 Medal
Mathematics
sabika13:
Group Title
I need some serious help please :(..
Make a summary table with these headings shown for each graph: Interval, Sign of Function, Sign of Slo…
updated one year ago
1 reply
No Medals Yet
Mathematics
sabika13:
Group Title
Has anyone read Handmaids tale? Can someone help me out!
updated one year ago
No Medals Yet
Mathematics
sabika13:
Group Title
How do I factor this: 16(x+1)^3 +2?
updated one year ago
6 replies
No Medals Yet
Mathematics
sabika13:
Group Title
450 = x(18-x)(20-2x) How do I solve this??
updated one year ago
3 replies
1 Medal
Mathematics
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