Questions Asked

Shaydenparis:
solve on interval [0,2pi), 7+5 sin x cos^2 x=0
 updated one year ago
 1 reply
 1 Medal

Shaydenparis:
solve the following equation on interval [0,2pi), tan(2x)+tanx=0
 updated one year ago
 No Medals Yet

Shaydenparis:
solve the following equation on interval [0,2pi) 1cosx=sinx
 updated one year ago
 2 replies
 1 Medal

Shaydenparis:
solve the following equation on interval [0,2pi) sin x square root 3 cos x=1
 updated one year ago
 7 replies
 No Medals Yet

Shaydenparis:
solve the following equation on interval [0,2pi) sin x square root 3 cos x=1
 updated one year ago
 No Medals Yet

Shaydenparis:
Solve the following at interval [0,2pi) 7+5sinxcos^2 x=0
 updated one year ago
 1 reply
 No Medals Yet

Shaydenparis:
Solve equation on the interval [0,2pi) of sinx=sin(2x)
 updated one year ago
 2 replies
 1 Medal

Shaydenparis:
prove secθ sinθ/ tanθ+cotθ = sin^2θ
 updated one year ago
 7 replies
 2 Medals

Shaydenparis:
prove secx sinx/ tanx+cotx = sin^2x
 updated one year ago
 1 reply
 No Medals Yet

Shaydenparis:
prove tanx/secx+cotx/cscx=sinx+cosx
 updated one year ago
 1 reply
 2 Medals

Shaydenparis:
prove cosx + 1/sin^3 = cscx/1cosx
 updated one year ago
 8 replies
 No Medals Yet

Shaydenparis:
prove cosx + 1/sin^3 = cscx/1cosx
 updated one year ago
 No Medals Yet

Shaydenparis:
tanx1/over/tanx+1=1cotx/over/1+cotx
 updated one year ago
 4 replies
 No Medals Yet

Shaydenparis:
prove siny +tany/over/ 1+secy=siny
 updated one year ago
 6 replies
 1 Medal

Shaydenparis:
prove sec^2θ/over/sec^2θ1=csc^2
 updated one year ago
 1 reply
 1 Medal

Shaydenparis:
prove sec^2θ/over/sec^2θ1=csc^2
 updated one year ago
 1 reply
 1 Medal

Shaydenparis:
prove
sec^2θ/over/sec^2θ1=csc^2
 updated one year ago
 2 replies
 1 Medal

Shaydenparis:
secxtanx=1/over/ sec x
 updated one year ago
 No Medals Yet

Shaydenparis:
prove:
sin y+tan y/ over /1+ sec y =sin y
 updated one year ago
 10 replies
 No Medals Yet

Shaydenparis:
(sinθ+cosθ)^2 + (sinθcosθ)^2 =2
 updated one year ago
 2 replies
 No Medals Yet

Shaydenparis:
secθ sinθ/ tanθ+cotθ = sin^2θ
 updated one year ago
 1 reply
 No Medals Yet

Shaydenparis:
secθ secθ/ tanθ+cotθ = sin^2θ
 updated one year ago
 2 replies
 No Medals Yet